Answer:
9.89 m/s
Explanation:
d = diameter of the space station = 20.0 m
r = radius of the space station
radius of the space station is given as
r = (0.5) d
r = (0.5) (20.0)
r = 10 m
a = acceleration produced at outer rim = 9.80 m/s²
v = speed at which it rotates
acceleration is given as
v = 9.89 m/s
Answer:
When an unbalanced force acts on a body the side with the greater force's dircetion makes the object move along its direction
Also to find the net force acting on the bofldy you can subtract the two force acting on the body
In case of balanced force the net force will always be 0
10km/10min is a legitimate speed. So is meters/sec, km/hour (kph), etc.
Kph is very common for vehicles:
10 km/10 min (60 min/hr) = 60 kph
Answer:
a = 7.5 m / s²
Explanation:
For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane
Y axis
N - W cos θ = 0
N = mg cos θ
X axis
W sin θ = m a
mg sin θ = m a
a = g sin θ
let's calculate
a = 9.8 cos 40
a = 7.5 m / s²
