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Vaselesa [24]
4 years ago
7

A ball is moving across a level platform 1.6m above the floor. After rolling off the ball hits the floor 20 from the base of the

platform. What is the velocity of the ball as it left the platform? Remember that the platform is level and that the ball is moving horizontally when it leaves the platform.
Physics
2 answers:
irakobra [83]4 years ago
8 0

Answer:

The correct answer is

35.01 m/s

Explanation:

To solve the question, we note the given variables thus

Height of platform S = 1.6 m

Distance from the platform the ball landed = 20 m

S = ut + 0.5gt² therefore 1.6 = 0.5 × 9.81 × t² or t = 0.57 s

Distance = 20 m  = velocity × time

Therefore velocity = Distance / time = 20 m/0.57 s = 35 m/s

sergij07 [2.7K]4 years ago
6 0

Answer:

 

Explanation:

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Space-faring astronauts cannot use standard weight scales (since they are constantly in free fall) so instead they determine the
valentinak56 [21]

Answer:

ma = 48.48kg

Explanation:

To find the mass of the astronaut, you first calculate the mass of the chair by using the information about the period of oscillation of the empty chair and the spring constant. You use the following formula:

T=2\pi\sqrt{\frac{m_c}{k}}     (1)

mc: mass of the chair

k: spring constant = 600N/m

T: period of oscillation of the chair = 0.9s

You solve the equation (1) for mc, and then you replace the values of the other parameters:

m_c=\frac{T^2k}{4\pi^2}=\frac{(0.9s)^2(600N/m)}{4\pi^2}=12.31kg    (2)

Next, you calculate the mass of the chair and astronaut by using the information about the period of the chair when the astronaut is sitting on the chair:

T': period of chair when the astronaut is sitting = 2.0s

M: mass of the astronaut plus mass of the chair = ?

T'=2\pi\sqrt{\frac{M}{k}}\\\\M=\frac{T'^2k}{4\pi^2}=\frac{(2.0s)^2(600N/m)}{4\pi^2}\\\\M=60.79kg (3)

Finally, the mass of the astronaut is the difference between M and mc (results from (2) and (3)) :

m_a=M-m_c=60.79kg-12.31kg=48.48kg

The mass of the astronaut is 48.48 kg

3 0
4 years ago
a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
enyata [817]

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

V2 = 0.0862m^3

Escaped volume = 0.0862 - 0.025 = 0.0612m^3

5 0
3 years ago
Describe how to measure the internal diameter of a beaker using a Vernier caliper?​
n200080 [17]

Answer:

Hope it helps..

Explanation:

Let n be the number of the vernier scale division which coincides with the main scale division. Rotate the vernier caliper 90° and repeat the steps 4 and 5 for measuring the internal diameter in perpendicular direction. To measure the depth, find the total reading and zero correction.

PLEASE MARK ME AS BRAINLIEST

3 0
3 years ago
Read 2 more answers
Observe: Air pressure is equal to the weight of a column of air on a particular location. Airpressure is measured in millibars (
lesya [120]

Answer:

a) When moving towards a high pressure center the pressure values ​​increase in the equipment

b) This area is called high prison since the weight of the atmosphere on top is maximum

Explanation:

A) A high atmospheric pressure system is an area where the pressure is increasing the maximum value is close to 107 Kpa, the other side as low pressure can have small values ​​85.5 kPa.

When moving towards a high pressure center the pressure values ​​increase in the equipment

B) This area is called high prison since the weight of the atmosphere on top is maximum

in general they are areas of good weather

6 0
3 years ago
Find the mass of an object if a 40 N of force causes the object to accelerate at 5.5 m/s/s
Murrr4er [49]

Answer:

<h3>The answer is 8 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{40}{5}  \\

We have the final answer as

<h3>8 kg</h3>

Hope this helps you

7 0
3 years ago
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