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Vaselesa [24]
3 years ago
7

A ball is moving across a level platform 1.6m above the floor. After rolling off the ball hits the floor 20 from the base of the

platform. What is the velocity of the ball as it left the platform? Remember that the platform is level and that the ball is moving horizontally when it leaves the platform.
Physics
2 answers:
irakobra [83]3 years ago
8 0

Answer:

The correct answer is

35.01 m/s

Explanation:

To solve the question, we note the given variables thus

Height of platform S = 1.6 m

Distance from the platform the ball landed = 20 m

S = ut + 0.5gt² therefore 1.6 = 0.5 × 9.81 × t² or t = 0.57 s

Distance = 20 m  = velocity × time

Therefore velocity = Distance / time = 20 m/0.57 s = 35 m/s

sergij07 [2.7K]3 years ago
6 0

Answer:

 

Explanation:

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A woman throws a javelin 35 mph at an angle 30 degrees from the ground. Neglecting wind resistance or the height the javelin thr
Anna71 [15]

Answer:

35 mph

Explanation:

The key of this problem lies in understanding the way that projectile motion works as we are told to neglect the height of the javelin thrower and wind resistance.

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When an object that moves in constant acceleration motion, the time neccesary for it to desaccelerate from a velocity v to 0, will be the same to accelerate the object from 0 to v. And the distance that the object will travel in both desaceleration and acceleration will be exactly the same.

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5 0
2 years ago
A pebble is released from rest at a certain height and falls freely, reaching an impact speed of 6 m/s at the floor. Next, the p
Anna71 [15]

Answer:

Explanation:

Let h be the height .

initial velocity in first case u = 0

final velocity v = 6 m /s

acceleration due to gravity g = 9.8 m /s²

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6² = 0 + 2 x 9.8 x h

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= 9 + 36

= 45 m

v = 6.7 m /s

8 0
3 years ago
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