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photoshop1234 [79]
3 years ago
14

The ΔHvap of a certain compound is 49.09 kJ·mol–1 and its ΔSvap is 53.69 J·mol–1·K–1. What is the boiling point of this compound

?
Chemistry
1 answer:
rusak2 [61]3 years ago
3 0
Hey there !

<span>Convert Joule to KJ :
</span>
1 j ---------------- 0.001 kj
53.69 j ----------- Kj

Kj = 53.69 * 0.001

=>  0.05369 Kj

T = ΔH / <span>ΔS

T = 49.09 / 0.05369

T = 914.32ºC</span>
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What is the correct balanced equation for the reaction that occurs when aqueous ammonium chloride reacts with aqueous barium nit
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Answer:

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

Explanation:

In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side

NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + NH_{4}NO_{3}

The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride  with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

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3 years ago
An ordered list of chemical substances is shown.
alina1380 [7]

Answer : The correct option is, (C) 2, 4 and 5.

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For example : Methane react with oxygen to give carbon dioxide and water.

CH_4+2O_2\rightarrow CO_2+2H_2O

In the given list of chemical substances, CuO,Cu_2O,Li_2O are in oxide form. They can not be both reactant and product of a single combustion reaction.

In the given list, C_2H_5NH_2 is the only hydrocarbon which shows a combustion reaction. That means C_2H_5NH_2 react with O_2 to give CO_2,H_2O and N_2 as a product.

The balanced combustion reaction of C_2H_5NH_2 is,

20C_2H_5NH_2+40O_2\rightarrow 40CO_2+7H_2O+10N_2

Therefore, the correct answer is, (C) 2, 4, and 5.

8 0
3 years ago
Which statement is true of diffusion?
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4 0
3 years ago
The heat of vaporization of 1-pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K.mol. What is the approximate b
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Answer:

Approximately 100 °C.

Explanation:

Hello,

In this case, since the entropy of vaporization is computed in terms of the heat of vaporization and the temperature as:

\Delta S_{vap}=\frac{\Delta H_{vap}}{T}

We can solve for the temperature as follows:

T=\frac{\Delta H_{vap}}{\Delta S_{vap}}

Thus, with the proper units, we obtain:

T=\frac{55500J/mol}{148J/(mol*K)} =375K\\\\T=102 \°C

Hence, answer is approximately 100 °C.

Best regards.

6 0
3 years ago
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