Answer:
i. + 22.5 m ii. 4.0 m
Explanation:
i. Image distance
Using the lens formula
1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown
So, we find v
1/v = 1/f - 1/u
= 1/+18 - 1/+90
= (5 - 1)/90
= 4/90
v = 90/4
= + 22.5 m
So the image is real and formed 22.5 m away on the other side of the lens.
ii Length of Shark
Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.
m = image distance/object distance
= v/u
= +22.5/+90
= 0.25
0.25 = image height/object height
So,
object height = image height/0.25
= 1.0 m/0.25
= 4.0 m
So, the length of the shark is 4.0 m
Answer:
2 miles
Explanation:
Jimmy walked forward 3 miles east (to the right)
Then, he backtracked and walked 1 mile west (to the left)
This can be written as:
3 - 1 = ?
3 - 1 = 2
Therefore, Jimmy traveled a total of 2 miles.
<h2>
Answer:distance and force</h2>
Explanation:
Let 
be the work done.
Let 
be the force applied.
Let 
be the displacement of the object.
Workdone by a object is defined as the dot product of force and displacement.
Since distance is the magnitude of displacement when force and displacement are in a same direction,
So,work done depends on force applied and distance.
