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bagirrra123 [75]
3 years ago
10

How to convert 40m/min to km/h? need step by step explanation​

Physics
2 answers:
AlekseyPX3 years ago
8 0

How to convert m/sec into km/hr

1 m = 1/1000 km; 1 sec = 1/3600 hr

1 m/sec = 3600/1000 km/hr = 18/5 km/hr

To convert m/sec into km/hr, multiply the number by 18 and then divide it by 5.

Need detail explanation? Go to bottom

Solved Example 1:

Convert 20 m/sec into km/hr.

Solution:

20 m/sec

Step 1:

Multiply 20 by 18

We have 20 * 18 = 360

Step 2:

Divide 360 by 5

360/5 = 72

Final Answer:

20 m/sec = 72 km/hr

Try yourself: Practice Sheet 1

Solved Example 2:

Convert 36 m/sec into km/hr.

Solution:

36 m/sec

Step 1:

Multiply 36 by 18

We have 36 * 18 = 648

Step 2:

Divide 648 by 5

648/5 = 129.6

Final Answer:

36 m/sec = 129.6 km/hr

Try yourself: Practice Sheet 2

Better Understanding:

The problem can be solved using an unitary method.

A shopkeeper sells each pencil for 5 cents. How much do 4 pencils cost? 4 * 5 cents= 20 cents, isn't it? What is the cost of 7 pencils? Yes, your guess is right. It is 7 * 5 cents = 35 cents.

Let us work out the problem in example 1 as it explained here.

20 m/sec = 360/5 = 72 km/hr

Hitman42 [59]3 years ago
7 0

Answer:

i have no clue i just need brailnly points

Explanation:

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B. A guitar string has a length of 0.90 m. When you pluck it, it plays a “C” that has a frequency of 256 Hz. How fast is the wav
horrorfan [7]

Answer:

461  m/s

Explanation:

Given the string length of guitar, l = 0.90 m

Frequency , f = 256 Hz

Using frequency, wavelength and velocity relation as

v=f λ

Here λ is wavelength.

Now for guitar string the length must be equal to half of wavelength, so

λ = 2l

Therefor above formula becomes as  

v = f×2l

Substituting the given values, we get

v =256×2×0.90

v = 460.8 m/s = 461 m/s

Thus, the wave moving back and forth along the string with velocity 461 m/s.

5 0
3 years ago
Find the magnitude of vector A = i - 2j + 3k O V14 10 O4
koban [17]

Answer:

The magnitude of the given vector is \sqrt{14}

Explanation:

For any given vector \overrightarrow{r}=x\widehat{i}+y\widehat{j}+z\widehat{k}

The magnitude is given by

|r|=\sqrt{x^2+y^2+z^2}

comparing with the given vector \overrightarrow{A}=1\widehat{i}-2\widehat{j}+3\widehat{k}

we get

x = 1, y = -2, z = 3

Thus the magnitude of vector A is

|r|=\sqrt{1^2+(-2)^2+3^2}\\\\\therefore |r|=\sqrt{14}

7 0
3 years ago
A bullet of mass 10g is fired from a gun. The bullet takes 0.003s to move through its barrel and leaves it with a velocity of 30
dsp73

Answer:

1,000 N

Explanation:

v=300 \text{ms}^{-1} ;u=0,t=000.3\text{s},m=0.01\text{kg}

Force exerted by the bullet on the rifle = \frac{m(v-u)}{\text{time}}

F = 1000N

Contextual Way:

Newton's second law of motion.

F=m a

Now to solve based on the current info, we shall assume that:-

The force exerted on the bullet was uniform across the entire duration of bullet leaving the barrel, i.e., 0.003 seconds {Not necessarily true for real life applications as the force will not be uniform from the point of hammer impact till the point of leaving the barrel. In reality you will get a Force profile across that entire duration}

We are not distinguishing between bullet and cartridge. {What you shall hold in your hand and load in a revolver is a cartridge containing the gunpowder, bullet etc. The bullet is the projectile at the mouth of the cartridge that actually leaves the barrel and hit the target. So when you are weighing in real life, you are not weighing the bullet, rather the cartridge as a whole}

Getting back to the question

Impulse equation for the bullet

∫F∗dt=∫m∗dv

Average impulse delivered= Change in momentum of the bullet

Assuming average force delivery

Favg∗∫dt=m∗∫dv

Favg∗0.003=0.010∗300

Favg=300∗10/3

Favg=1000N

7 0
1 year ago
A vector has a component of 10 m in the x-direction, a component of 10 m in the y-direction, and a component of 5 m in the z dir
Kobotan [32]

The magnitude of this vector is 15

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

Let vector be = a

component of vector in x direction = 10 i

component of vector in y direction = 10 j

component of vector in z direction = 5 z

vector a = 10 i + 10 j + 5 z

magnitude of vector a = |a| = \sqrt{10^{2} +10^{2} + 5^{2}    }

                                             = 15

To learn more about vector here

brainly.com/question/24256726

#SPJ4

8 0
2 years ago
State Archimedes' principle
OlgaM077 [116]

Explanation:

Archimedes' principle states that the upward buoyant force which is exerted on body when immersed  whether fully submerged or partially in the fluid is equal to weight of fluid which body displaces and this force acts in upward direction at center of mass of displaced fluid.

Thus,

<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>

6 0
2 years ago
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