All categories

3 years ago

How to convert 40m/min to km/h? need step by step explanation

Physics

2 answers:

AlekseyPX3 years ago

8 0

How to convert m/sec into km/hr

1 m = 1/1000 km; 1 sec = 1/3600 hr

1 m/sec = 3600/1000 km/hr = 18/5 km/hr

To convert m/sec into km/hr, multiply the number by 18 and then divide it by 5.

Need detail explanation? Go to bottom

Solved Example 1:

Convert 20 m/sec into km/hr.

Solution:

20 m/sec

Step 1:

Multiply 20 by 18

We have 20 * 18 = 360

Step 2:

Divide 360 by 5

360/5 = 72

Final Answer:

20 m/sec = 72 km/hr

Try yourself: Practice Sheet 1

Solved Example 2:

Convert 36 m/sec into km/hr.

Solution:

36 m/sec

Step 1:

Multiply 36 by 18

We have 36 * 18 = 648

Step 2:

Divide 648 by 5

648/5 = 129.6

Final Answer:

36 m/sec = 129.6 km/hr

Try yourself: Practice Sheet 2

Better Understanding:

The problem can be solved using an unitary method.

A shopkeeper sells each pencil for 5 cents. How much do 4 pencils cost? 4 * 5 cents= 20 cents, isn't it? What is the cost of 7 pencils? Yes, your guess is right. It is 7 * 5 cents = 35 cents.

Let us work out the problem in example 1 as it explained here.

20 m/sec = 360/5 = 72 km/hr

Hitman42 [59]3 years ago

7 0

Answer:

i have no clue i just need brailnly points

Explanation:

You might be interested in

Sum of number of protons and neutrons in the nucleus

Alina [70]

That's the "Atomic Mass" of the atom.

4 0

4 years ago

Please Help

Degger [83]

Explanation:

The initial kinetic energy $KE_0$ is

$KE_0 = \frac{1}{2}mv_0^2 = \frac{1}{2}(400\:\text{kg})(10\:\text{m/s})^2$

$\:\:\:\:\:\;\:= 2×10^4\:\text{J} = 20\:\text{kJ}$

The final kinetic energy $KE$ is

$KE = \frac{1}{2}mv^2 = \frac{1}{2}(400\:\text{kg})(30\:\text{m/s})^2$

$\:\:\:\:\:\:\:= 1.8×10^5\:\text{J} = 180\:\text{kJ}$

The work done W on the car is

$W = \Delta{KE} = KE - KE_0$

$\:\:\:\:\:\:\:= 180\:\text{kJ} - 20\:\text{kJ} = 1.6×10^5\:\text{J}$

The power expended P is

$P = \dfrac{W}{t} = \dfrac{1.6×10^5\:\text{J}}{15\:\text{s}} = 10667\:\text{Watts}$

$\:\:\:\:\:= 10.7\:\text{kW}$

8 0

3 years ago

A uniform ladder is 10 m long and weighs 400 n. it rests with its upper end against a frictionless vertical wall. its lower end

Nikolay [14]

<h3><u>Answer;</u></h3>

200 N

<h3><u>Solution;</u></h3>

Given ;

Weight = 400 N

Length of the ladder = 10 m

Using the equation;

Torque = d x F, where F is the perpendicular force and d is the distance

Calculating torque about the lower end,

Tweight = Twall

400N(5cos30) = F (10sin30)

F = 200 N

Therefore, the magnitude of force exerted on the peg by the ladder is 200 N

5 0

4 years ago

A cart travels down a ramp at an average speed of 5.00 centimeters/second. What is the speed of the cart in miles/hour? (Remembe

viva [34]

Set up the problem with the conversion rates as fractions where when you multiply the units cancel out leaving the desired units behind.

$( \frac{ 5 cm}{1 sec} ) *( \frac{1m }{100cm})*( \frac{1km}{1000m} )*( \frac{1mi}{1.6km} ) = 0.00003125 mi/sec \\ \\ ( \frac{0.00003125 mi}{1sec} )*( \frac{60sec}{1min} )*( \frac{60min}{1hr} )=0.1125 mi/hr$