Step-by-step explanation:
20x = 4x +16
16x = 16
x=1
multiply the 2 into the absolute value bars. check if there are negatives. if there aren't, bars can be removed. solve as normal
Answer:
A.
Step-by-step explanation:
The a^3 would cancel out, currently leaving just b^5 on the top and ab on the bottom. The b would also cancel out, finally leaving just b^4/a. Therefore A is the answer equivalent to the original expression.
Answer:
Use an online converter but there is something you should know
Step-by-step explanation:
There are two systems of measurement. The Imperial system (inch, mile, cups, ounces) and the Metric system (millimeter, centimeter, gram, kilogram).
Converting measurements in the imperial system by memory is very hard, but converting measurements in the metric system is more simple.
It is easier to learn by images so here is an image that explains it
Keep in mind that measurements like inches and centimeters are for distance, while gram and ounces are for weight.
What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M
AURORKA [14]
<h3><u>given</u><u>:</u></h3>
<u>
</u>
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the mode and median of the given numbers set.
<h3><u>solution</u><u>:</u></h3><h3><u>mode</u><u>:</u></h3>
the most frequently occurred number.

<h3><u>median</u><u>:</u></h3>
first arrange all the numbers in either decending or ascending order, then find the number in the middle.


<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>median</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>following</u><u> </u><u>data</u><u> </u><u>set</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>mode</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>and</u><u> </u><u>3</u>
Answer:
3.33 and 1/3
Step-by-step explanation:
"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.
But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.