If oxygen is removed from a sample of air as iron rust, what happens to the particle pressure of oxygen in the air?
1 answer:
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Answer:
The answer is
<h2>19.31 g/cm³</h2>Explanation:
The density of a substance can be found by using the formula
From the question
mass of gold = 475.09g
volume = 24.6 cm³
The density of the gold is
We have the final answer as
<h3>19.31 g/cm³</h3>Hope this helps you
The question is incomplete. Complete question is attached below:
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Correct Answer is : 54 131Xe
Reason:
Emission of beta particle from radioactive material increases atomic number by one, but atomic mass number donot change.
In present case, the reactant is 53 131 I. When, iodine emits beta particle i.e. electron, it atomic number increases by one. Hence, it gets converted into Xe. Atomic number of Xenon is 54.
.................................................................................................................
Correct Answer is : 54 131Xe
Reason:
Emission of beta particle from radioactive material increases atomic number by one, but atomic mass number donot change.
In present case, the reactant is 53 131 I. When, iodine emits beta particle i.e. electron, it atomic number increases by one. Hence, it gets converted into Xe. Atomic number of Xenon is 54.