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Brilliant_brown [7]
3 years ago
15

Determine the density of gold if a 475.09g sample occupy a space of 24.6cm^3

Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

The answer is

<h2>19.31 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of gold = 475.09g

volume = 24.6 cm³

The density of the gold is

density =  \frac{475.09}{24 .6}  \\  = 19.3126016...

We have the final answer as

<h3>19.31 g/cm³</h3>

Hope this helps you

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Oleic acid (C_{17}H_{33}COOH) consist of 17 carbon atoms attached to 33 hydrogen atoms with one double bond between two carbon atoms and one carboxylic group i.e.(-COOH). When oleic acid is hydrogenated or reacts with hydrogen in the presence of catalyst, then the carbon carbon double breaks by the addition H-H and alkane product i.e. stearic acid  (C_{17}H_{35}COOH) is formed.

The chemical reaction is shown in the image.

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3 years ago
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Answer:

D. 40 % increase  

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Explanation: what i just said

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Answer:

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