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pychu [463]
3 years ago
12

Why does changing the volume of a container change the pressure of the gas in it?​

Chemistry
2 answers:
klio [65]3 years ago
6 0

Changing the volume increases the area that the molecules collide with so the force is spread over a larger area.

Setler79 [48]3 years ago
4 0

Answer:

the answer is D

Explanation:

i just did the test and got it right

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Which argument is correct
torisob [31]

Answer:

The first agrument.

Explanation:

Because only heat can be transfered. Thats why if you put something hot in a refridgerator the heat energy will go off in the fridge and powers the cold energy. Im pretty sure this is right this is what my teachers tought me so i hope they right

6 0
2 years ago
How many distinct and degenerate p orbitals exist in the second electron shell, where n = 2?
viktelen [127]

Answer: 3 degenerate orbitals are obtained

Explanation:

The p orbital can house a maximum of 6 electrons splitting the degenerate orbital into 3 and having each contain a maximum of 2 electrons each

8 0
3 years ago
If Thomson’s atomic theory was accurate, what would the results of Rutherford’s gold foil experiment have been?
Arisa [49]

Answer:

If Thomson's atomic theory was accurate, the positively charged particles would have gone through the foil.

8 0
2 years ago
Which of the following statement is not true?
konstantin123 [22]
I believe C is the answer <span />
4 0
3 years ago
14. A cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a
grin007 [14]

59.78175 kPa is the pressure inside the container when a cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a 4.00 L container at 24.0°C.

<h3>What is an ideal gas equation?</h3>

An ideal gas equation states the relationship between the moles of the substance, temperature, pressure, and volume. The ideal gas equation is given as, PV=nRT

Given data:

P_1=48.0 atm

V_1=3T_1=17.0°C

P_2=?

V_2=4.00 L

T_2=24.0°C

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{48.0 atm X 35.0 mL}{17.0} = \frac{P_2X 4000 ml L}{24.0}

P_2= 0.59 atm = 59.78175 kPa

Hence, 59.78175 kPa is the pressure inside the container when a cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a 4.00 L container at 24.0°C.

Learn more about the  ideal gas equation here:

brainly.com/question/22368165

#SPJ1

4 0
2 years ago
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