I'm happy to help but do you have the options?
Answer:
pH = 11, The solution is Basic.
Explanation:
We know that;
[OH-] [H+] = 1 × 10^-14
we are given; [OH-] as 1 x 10^ -3 M
Therefore, we can get the [H+] by;
[H+] = 1 × 10^-14/[OH-]
= 1 × 10^-14 M/1 x 10^ -3 M
= 1 × 10^-11 M
But; pH = - log [H+]
Thus,
pH = - log (1 ×10^-11 M)
= 11
pH = 11, which means the solution is basic.
Yes you would keep your memories
Answer:
The new volume of the sample is halved.
Explanation:
Data obtained from the question include the following:
Initial volume (V1) = V
Initial temperature (T1) = T
Initial pressure (P1) = P
Final pressure (P2) = quadrupled = 4P
Final temperature (T2) = doubled = 2T
Final volume (V2) =?
Thus, we can obtain the new volume of the same by using the combined gas equation as shown below:
P1V1 /T1 = P2V2 /T2
P × V/T = 4P × V2/2T
Cross multiply
T × 4P × V2 = P × V × 2T
Divide both side by T × 4P
V2 = (P × V × 2T) / (T × 4P)
V2 = V/2
V2 = ½V
Therefore, the new volume of the sample is halved .
