The diagonals of an isosceles trapezoid are 3x + 7 and 5x – 11. What is the value of x?
2 answers:
In a trapazoid the diagonals are the same so therefore the two equations equal echother
3x+7=5x-11 solve for x by combining like terms
18=2x then divide to unto multiplication
9=x
9 is the value of x
I hope I've helped!
Diagonals are congruent. (since the trapezoid is isosceles)
3x+7= 5x-11
Add 11 on both sides.
3x+18= 5x
Subtract 3x on both sides.
18= 2x
Divide by 2 into both sides.
x=9
I hope this helps!
~kaikers
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