Question

The diagonals of an isosceles trapezoid are 3x + 7 and 5x – 11. What is the value of x?

Answer 1

In a trapazoid the diagonals are the same so therefore the two equations equal echother

3x+7=5x-11  solve for x by combining like terms

18=2x  then divide to unto multiplication

9=x

9 is the value of x

I hope I've helped!

Answer 2

Diagonals are congruent. (since the trapezoid is isosceles)

3x+7= 5x-11

Add 11 on both sides.

3x+18= 5x

Subtract 3x on both sides.

18= 2x

Divide by 2 into both sides.

x=9

I hope this helps!
~kaikers