(a).
The product of two binomials is sometimes called FOIL.
It stands for ...
the product of the First terms (3j x 3j)
plus
the product of the Outside terms (3j x 5)
plus
the product of the Inside terms (-5 x 3j)
plus
the product of the Last terms (-5 x 5)
FOIL works for multiplying ANY two binomials (quantities with 2 terms).
Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .
Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.
Whenever you have
(the sum of two things) x (the difference of the same things)
the product is going to be
(the first thing)² minus (the second thing)² .
So in (a), that'll be (3j)² - (5)² = 9j² - 25 .
You could find the product with FOIL, or with this easier tool.
______________________________
(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:
(4h + 5) x (4h + 5) .
You can do the product with FOIL, or use another little tool:
The square of a binomial (4h + 5)² is ...
the square of the first term (4h)²
plus
the square of the last term (5)²
plus
double the product of the terms 2 · (4h · 5)
________________________________
(c).
Use the tool I gave you in part-a . . . twice .
The product of the first 2 binomials is (g² - 4) .
The product of the last 2 binomials is also (g² - 4) .
Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .
We know is a horizontal line, so, if it passes through 1,-5, it also passes through "whatever", -5, like 20, -5 or 1000000, -5, or -100000000, -5 and so on.
so, let's pick another point say -7, -5, check the picture below, and let's check about the equation that runs through it,
Answer:
(a) The probability of more than one death in a corps in a year is 0.1252.
(b) The probability of no deaths in a corps over 7 years is 0.0130.
Step-by-step explanation:
Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.
The random variable
.
The probability function of a Poisson distribution is:
![P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cfrac%7Be%5E%7B-%5Clambda%7D%5Clambda%5E%7Bx%7D%7D%7Bx%21%7D%3B%5C%20x%3D0%2C1%2C2%2C...)
(a)
Compute the probability of more than one death in a corps in a year as follows:
P (X > 1) = 1 - P (X ≤ 1)
= 1 - P (X = 0) - P (X = 1)
![=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252](https://tex.z-dn.net/?f=%3D1-%5Cfrac%7Be%5E%7B-0.62%7D%280.62%29%5E%7B0%7D%7D%7B0%21%7D-%5Cfrac%7Be%5E%7B-0.62%7D%280.62%29%5E%7B1%7D%7D%7B1%21%7D%5C%5C%3D1-0.54335-0.33144%5C%5C%3D0.12521%5C%5C%5Capprox0.1252)
Thus, the probability of more than one death in a corps in a year is 0.1252.
(b)
The average deaths over 7 year period is: ![\lambda=7\times0.62=4.34](https://tex.z-dn.net/?f=%5Clambda%3D7%5Ctimes0.62%3D4.34)
Compute the probability of no deaths in a corps over 7 years as follows:
![P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130](https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5Cfrac%7Be%5E%7B-4.34%7D%284.34%29%5E%7B0%7D%7D%7B0%21%7D%3D0.01304%5Capprox0.0130)
Thus, the probability of no deaths in a corps over 7 years is 0.0130.
Answer:
5%
Step-by-step explanation:
15/300 = 0.05
5%
Answer:
0.5cm
Step-by-step explanation:
Using the sine rule