The amount of money borrowed is $ H
Time for borrowing is 25 years
Amount paid per month M
Amount paid per year 12M
Interest rate paid=I
Let the payment method be simple interest method, then:
I=(PRT)/100
plugging in our values we have:
I=(H×R×M)/100
hence:
I=HRM/100
Step-by-step explanation:
3 x^3-15x^2+18x 3(x^3-5x^2+6x)
So you can use
$21.95 + $.19x = $18.95 + $.21x
Answer:
x=7
Step-by-step explanation:
3(2x - 5) = 9(10 - x)
6x-15=90-9x
6x+9x=90+15
15x=105
x=7
Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.