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lara [203]
3 years ago
13

A rocket's mass decreases as it burns fuel. the equation of motion for a rocket in vertical flight can be obtained from newton's

law and is
Physics
1 answer:
Talja [164]3 years ago
4 0

<span>The equation of motion for a rocket in vertical flight can be obtained from newton’s second law of motion and is constant-mass system. The equation of motion for a body mass varies with time and mass. When force acts on rocket, the rocket will accelerate in the direction of force. Therefore, force is equal to the change in momentum per change in time. For constant mass, force equals mass times acceleration.</span>

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Q 1 . How many significant figures are in the following measurement? 0.0009(1 point)
Crazy boy [7]

Here we have some questions about experimental errors.

Q1) We want to see how many significant figures have the measure:

0.0009

The number of significant figures is the number of known digits that are not the leading zeros.

Here we can see four leading zeros, and a single-digit different than zero, which is a 9.

Then we have only one significant figure, the 9.

Q2) Here we will use the measure that is the less exact, as the error of that measure may be larger than the smaller significant figures of the other measures.

Then:

31.2 lb + 38.02lb + 45 lb

The worst measure is 45lb, so the smallest significant figure that we should use is the first one at the left of the decimal point, then we need to round the other two measures to the next whole number, we will get:

31 lb + 38 lb + 45 lb = 114lbs

Q3) We know that the measure is 11.5 seconds and the uncertainty of 1.7%, then the uncertainty will be the 1.7% of the above measure:

(1.7%/100%)*11.5 s = 0.1955 s

Notice that our measure has one significant figure after the decimal point, so we need to round the error to the same significant figure.

0.1955 s ≈ 0.2s

Then the measure is:

11.5 s ± 0.20 s

Q4) We have the measure:

312.0 mph ± 3.9 mph.

The percent uncertainty will be the quotient between the error and the measure times 100%, or:

(3.9 mph/312.0 mph)*100%  = 1.25%

This is a percent error, we do not need to round this.

If you want to learn more, you can read:

brainly.com/question/17339020

5 0
2 years ago
||||| A 1.5 kg block and a 2.5 kg block are attached to opposite ends of a light rope. The rope hangs over a solid, frictionless
amid [387]

Answer

The lighter block will have the Positive Acceleration that is +2.45 m/s square.

A (1.5 Kg) = + 2.45 m/s square

Explanation:

To solve this there is a hard way to do this and there is an easy way to do this. The hard way is to solve Newton's second law for each block individually and then combine them and you get two equations with two unknowns. you try your best to solve the algebra without losing any sins but lets be honest it usually goes wrong.

So the easy way to do this the way to get the magnitude of the acceleration of the blocks. That is to say that i want to know the magnitude at which 2.5 Kg block accelerates or 1.5 Kg block accelerates when the the blocks were released.

Take the net external force that tries to make system go and divide it by total mass of the the system.

<u>A </u><u>(of System) = </u><u>F</u><u>(net external force) / </u><u>m</u><u> (total mass of system)</u>

This is the quick way to know the magnitude of acceleration of the objects in the system. But this is only possible if the system is moved in same magnitude of acceleration that is 2.5 Kg block will move downward and 1.5 Kg block will move upward with the same magnitude. So here in this case we have friction-less pulley and the blocks will move with the same magnitude of acceleration.

To find the external forces

External forces are the forces which exerted on the objects in our system from the objects outside of our system. So one external force is the force of gravity. Both 2.5 Kg block and the force of gravity will be in downward direction.

Force of gravity on 2.5 Kg block

F = + (2.5 x 9.8) = 24.5

After releasing the rope the 2.5 Kg block will drive the system and accelerates in downward direction so It will be a positive force.

Force of gravity on 1.5 Kg block

F = - (1.5 x 9.8) = 14.7

The force of gravity on 1.5 Kg block will be negative because it will accelerate in upward or opposite direction of the force of gravity. Because the whole system is moving in one direction but the force of gravity on 1.5 Kg block is opposing the acceleration of the system.

Now divide the the Net external forces by total mass of the blocks that is

<u>A </u><u>(of System) = </u><u>F</u><u>(net external force) / </u><u>m</u><u> (total mass of system)</u>

A = (+ 24.5 - 14.7) / 2.5 + 1.5

A = 9.8 / 4

A = 2.45 meter per second square

So the Acceleration of 2.5 Kg block will be Negative that is -2.45 m/s square. Since block is accelerating down and we usually treat down as negative.

A (1.5 Kg) = - 2.45 m/s square

So the Acceleration of 1.5 Kg block will be Positive that is +2.45 m/s square. Since block is accelerating up and we usually treat up as positive.

A (1.5 Kg) = + 2.45 m/s square

4 0
3 years ago
Question 1 (Multiple Choice Worth 2 points)
Masja [62]

Answer:

the crest of one wave to the crest of the next wave

Explanation:

6 0
2 years ago
Suggest and explain two ways to reduce heat loss through the doors of the house.
emmainna [20.7K]
Keep the doors closed and make sure there isnt lots of open space between the door and the frame
8 0
3 years ago
Ship 1 has 4 times the mass of ship 2. They both have equal kinetic energy. How much faster( by what factor) is ship 2 moving?
Stolb23 [73]

2

Explanation:

Let us assume the mass of ship 2 = K

Mass of ship 1 = 4K

Condition:

Both ships have the same mass

The kinetic energy of a body is the energy due to the motion of it.

It is expressed as:

  K.E = \frac{1}{2}  m v^{2}

m is the mass of the ship

v is the velocity;

Since both ships have equal velocity;

 

                K.E of ship 1 = K.E of ship 2

  \frac{1}{2}  m v^{2}  of ship 1 =   \frac{1}{2}  m v^{2} of ship 2

    multiply through by 2;

     m_{1} v_{1} ^{2}  = m_{2} v_{2} ^{2}

    4k x v_{1} ^{2} = k x v_{2}^{2}

     

       dividing by k;

   4 v_{1} ^{2} = v_{2}^{2}

taking square root of both sides

   V₂ = 2V₁

learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

4 0
2 years ago
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