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spayn [35]
3 years ago
9

Didn't know what type of science it was? But pls helpp

Physics
1 answer:
Alla [95]3 years ago
8 0
The answer is the third one down. New evidence may contradict the old evidence of a certain theory.
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The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies
mestny [16]

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

Global Positioning System: 1227 to 1575 MHz

microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

8 0
3 years ago
Magnitude of force F experienced by a certain object moving with speed v is given by F=Kv race to 2, where K is constant. Find t
My name is Ann [436]
<h2>Answer:</h2>

MT⁻¹

<h2>Explanation:</h2>

Given equation:

F = Kv        --------------(i)

Where;

F = Magnitude of force experienced by the object

v = speed at which the object is moving

K = constant.

To get the dimension of K, follow the following steps:

i. <em>Make K subject of the formula in equation(i)</em>

K = F / v

ii.<em> Get the dimension of force F and speed v</em>

Dimension of force = MLT⁻²

Dimension of velocity = LT⁻¹

iii.<em> Substitute these dimensions into the result of (i) above;</em>

K = MLT⁻² / LT⁻¹

iv. <em>Simplify the result in (iii)</em>

<em>First, the </em><em>L</em><em>s in the numerator and denominator will cancel out</em>

K = MT⁻² / T⁻¹

<em>Next, the </em><em>T</em><em>s will be expressed as follows</em>

K = MT⁻² x T¹           [using the law of indices]

K = MT⁻²⁺¹

K = MT⁻¹

Therefore, the dimension of K is MT⁻¹

6 0
3 years ago
John rides his motorcycle with a constant speed of 40 miles per hour. How far can he travel in 1/2 an hour?
Nuetrik [128]
The answer would be 60 miles.
5 0
3 years ago
Using the midpoint and the distance formulas, calculate he coordinate of the midpoint and the length of the segment.
arsen [322]

Answer:

Explanation:

Formula to calculate the distance between two points (x_1,y_1) and (x_2,y_2) is,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Therefore, length of CD having coordinates C(3,1) and D(3, 3),

CD = \sqrt{(3-3)^2+(1-3)^2}

     = 2 units

Formula to find the midpoint of CD is,

M = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

   = (\frac{3+3}{2},\frac{1+3}{2})

   = (3, 2)

Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.

7 0
4 years ago
If you are given force and time you can determine power if you can know
Ivenika [448]

Answer: Distance

Explanation: because with force and distance we can determine work, and with work and time we can determine power.

7 0
3 years ago
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