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3 years ago

What advantages do space telescopes have over Earth telescopes?

Physics

2 answers:

vampirchik [111]3 years ago

8 0

Answer:

You don’t have to deal with the atmosphere of the earth. It points to the potential of the space program.

Explanation:

natulia [17]3 years ago

3 0

Devonshire Street telescopes how are earths telescopes that’s all me Siri you are I go to the store area

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0.0135 kg of steam at 100°C is

lora16 [44]

Answer:

33333.35 kg

Explanation:

I got it right on Acellus, rounded to 33300 sigfigs

8 0

3 years ago

ANSWER ASAPPPPPPPPPPPP

Free_Kalibri [48]

My teacher said it was c

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3 years ago

Read 2 more answers

The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7

My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0

3 years ago

A parcel of air at 5 km. and an initial temperature of 10°C altitude descends to 3 km altitude at the unsaturated adiabatic laps

Alchen [17]

Answer:

30 degrees Celsius

Explanation:

With unsaturated adiabatic lapse rate water vapour does not have to change state from gaseous to liquid.

7 0

3 years ago

A car is moving in uniform circular motion. If the car's speed were to double to keep the car moving with the same radius, the a

Anestetic [448]

Answer:

Increase by a factor of 4.

Explanation:

The acceleration of a car moving with speed v in a circle of radius R is given by:

$a=\frac{v^2}{R}.$

Now if we double the speed $v$ in the equation above, it becomes $2v$ . Thus:

$a=\frac{v^2}{R}\:\: {\rightarrow}\:\: a_n=\frac{(2v)^2}{R}=4\frac{v^2}{R}=4a.$

Therefore the acceleration is increased by a factor of 4.

7 0

3 years ago