Answer:
by magnetising a piece of iron with a magnet
Explanation:
Answer:
(a)
(b) Kinetic Energy of planet with mass m₁, is KE₁ = 1.068×10³² J
Kinetic Energy of planet with mass m₂, KE₂ = 2.6696×10³¹ J
Explanation:
Here we have when their distance is d apart
Energy is given by
Conservation of linear momentum gives
m₁·v₁ = m₂·v₂
From which
v₂ = m₁·v₁/m₂
At equilibrium, we have;
which gives
multiplying both sides by m₂/m₁, we have
Such that v₁ =
Similarly, with v₁ = m₂·v₂/m₁, we have
From which we have;
and
The relative velocity = v₁ + v₂ =
v₁ + v₂ =
(b) The kinetic energy KE =
Just before they collide, d = r₁ + r₂ = 3×10⁶+5×10⁶ = 8×10⁶ m
= 10333.696 m/s
=2583.424 m/s
KE₁ = 0.5×2.0×10²⁴× 10333.696² = 1.068×10³² J
KE₂ = 0.5×8.0×10²⁴× 2583.424² = 2.6696×10³¹ J.
Vertically we can say
<span>Vertical acceleration = - g </span>
<span>Vertical velocity = u sinѲ - gt [Ѳ = 42; u = 12 m/s] </span>
<span>Vertical displacement = u sinѲt - (1/2) g t^2 + 9.5 </span>
<span>When the rock hits the ground, its vertical displacement will be zero. So we can say.. </span>
<span>u sinѲt - (1/2) g t^2 + 9.5 = 0 </span>
<span>I'll rearrange this .... </span>
<span>- (1/2) g t^2 + u sinѲt + 9.5 = 0 </span>
<span>Can you see that we now have a quadratic in t? </span>
<span>Using the well known formula </span>
<span>t = [ - u sinѲ ± √( u^2 sin^2Ѳ - 4(( - (1/2)g * 9.5))] / (- g) </span>
<span>t = [- u sinѲ ± √( u^2 sin^2Ѳ + 19g)] / (-g) </span>
<span>t = [- 8.03 ± √(250.86)] / (-9.81) </span>
<span>t = [- 8.03 ± 15.84] / (-9.81) </span>
<span>t = (- 8.03 + 15.84) / (-9.81) or t = (-8.03 - 15.84) / (-9.81) </span>
<span>t = - 0.8 or t = 2.43 </span>
<span>Well, a negative time has no meaning so </span>
<span>t = 2.43 seconds. </span>
Answer:
Launch velocity of the fleas = 1.80 m/s
Explanation:
Optimal launch angle is the angle that guarantees the maximum horizontal distance covered.
Optimum launch angle = 45°
The horizontal distance covered by a projectile is given as Range
R = (u² sin 2θ)/g
u = initial velocity of the projectile (flea) = ?
R = range = 33 cm = 0.33 m
θ = 45°
2θ = 2 × 45° = 90°
Sin 90° = 1
g = acceleration due to gravity = 9.8 m/s²
R = (u²/g)
u² = Rg = 0.33 × 9.8 = 3.234
u = 1.80 m/s
Hope this helps!!!
I’d love to help, but I can barely understand what you put