Answer:
mu=12Tm^2
Explanation:
the magnetic moment mu of a single loop is given by:

where I is the current, B is the magnetic field and A is the area of the loop. By replacing we obtain:

hope this helps!!
Answer:39.88 rad/s
Explanation:
Given
mass of cylinder m_1=18 kg
radius R=1.7 m
angular speed 
mass of
dropped at r=0.3 m from center
let
be the final angular velocity of cylinder
Conserving Angular momentum





<u>Answer:</u>
Both the objects A and B will have the same acceleration.
<u>Explanation
:</u>
The objects will have the same acceleration as both are under free fall condition. When objects are under the free fall condition, the only force that acts on the object is its weight.
Weight is the force acting on a body of some mass, and the formula for finding the weight of a body is- Weight = mass × acceleration due to gravity(g).
Therefore, here the different weight is due to the difference masses of both bodies, and not due to the different acceleration values.
Answer:
a) 90 kJ
b) 230.26 kJ
Explanation:
The pressure at the first point
= 10 bar —> 10 x 102 = 1020 kPa
The volume at the first point
= 0.1 m^3
The pressure at the second point
= 1 bar —> 1 x 102 = 102 kPa
The volume at the second point
= 1 m^3
Process A.
constant volume V = C from point (1) to P = 10 bar.
Constant pressure P = C to the point (2).
Process B.
The relation of the process is PV = C
Required
For process A & B
(a) Sketch the process on P-V coordinates
(b) Evaluate the work W in kJ.
Assumption
Quasi-equilibrium process
Kinetic and potential effect can be ignored.
Solution
For process A.
V=C
There is no change in volume then

The work is defined by

║
V║limit 1--0.1
90 kJ
Process B
PV=C
By substituting with point (1) C = 10^2 x 1= 10^2
The work is defined by

║
ln(V)║limit 1--0.1
=230.26 kJ