Answer:
773.25 Hz
Explanation:
Concept : In an open organ pipe in fundamental mode of vibration
wave length of wave λ = 2L
where L is length of the pipe
frequency = velocity of sound / λ
Given values: fundamental frequency = 288 Hz
fluid is air. velocity of sound = 340 m/s
⇒ 288 = 340/2L
⇒L = 59.02 cm
The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then, frequency of note produced will also be changed .
We know that velocity of sound is inversely proportional to square root of molar mass of gas
velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)
Now, frequency = velocity of sound / λ
= 912.75 / (2 x 0.5902)
= 773.25 Hz
Answer:
B and D
Explanation
Gravitational potential energy does not relate to graphs and it is about a moving object so b and d would not be correct
Answer:
Explanation:
Natural length of the string is given as
length of the string while block is hanging on it
extension in length is given as
now we have strain in the string is given as
similarly we will have cross-sectional area of the string is given as
now the stress in the string is given as
Now Young's Modulus is given as
Answer:
10.93m/s with the assumption that the water in the lake is still (the water has a speed of zero)
Explanation:
The velocity of the fish relative to the water when it hits the water surface is equal to the resultant velocity between the fish and the water when it hits it.
The fish drops on the water surface vertically with a vertical velocity v. Nothing was said about the velocity of the water, hence we can safely assume that the velocity if the water in the lake is zero, meaning that it is still. Therefore the relative velocity becomes equal to the velocity v with which the fish strikes the water surface.
We use the first equation of motion for a free-falling body to obtain v as follows;
v = u + gt....................(1)
where g is acceleration due to gravity taken as 9.8m/s/s
It should also be noted that the horizontal and vertical components of the motion are independent of each other, hence we take u = 0 as the fish falls vertically.
To obtain t, we use the second equation of motion as stated;
Given; h = 6.10m.
since u = 0 for the vertical motion; equation (2) can be written as follows;
substituting;
Putting this value of t in equation (1) we obtain the following;
v = 0 + 9.8*1.12
v = 10.93m/s
Force of gravity = 'G' (mass₁)(mass₂) / (distance)²
'G' is the gravitational constant for SI units = 6.67 x10⁻¹¹ newton-meter²/kg²
You said that the force is <u>2.99 x 10⁻¹⁰</u> = (6.67x10⁻¹¹) (4) (7) / D²
Multiply each side by D² : 2.99 x 10⁻¹⁰ D² = (6.67x10⁻¹¹) (28)
Divide each side by 2.99 x 10⁻¹⁰ : D² = (28) (6.67 x10⁻¹¹) / (2.99 x 10⁻¹⁰)
Take the square root of each side: D = square root of all that
Stuff it through my calculator:
D = square root of [ (28) (6.67 x10⁻¹¹) / (2.99 x 10⁻¹⁰) ] =
√ ( 6.2462...) meters² =
<em>2.5 meters </em> (rounded)
===================
To get the feel:
-- The book weighs about 8.8 pounds (big book)
-- The lamp weighs about 15.4 pounds
-- They're about 8.2 feet apart.
-- The strength of the gravitational force
between them is about 0.000 000 001 075 of an ounce .