Answer:
Explanation:
Given
Horizontal bar rises with 300 mm/s
Let us take the horizontal component of P be
where 
is angle made by horizontal bar with x axis
Velocity at y=150 mm
thus 
position of
Velocity at this instant
The width of the playroom is 4 m
Answer:
11.64225 m
Explanation:A = 45 m/s – 15m/s / 6s
A = 5m/s^2
Answer:
magnitude of the induced emf in the coil is 0.0153 V
Explanation:
Given data
no of turns = 20
area = 0.0015 m²
magnitude B1 = 4.91 T/s
magnitude B2 = 5.42 T/s
to find out
the magnitude of the induced emf in the coil
solution
we know here
emf = -n A d∅ /dt
so here n = 20 and
A = 0.0015
and d∅ = B2 - B1 = 5.42 - 4.91
d∅ = 0.51 T and dt at 1 sec
so put all value
emf = -n A d∅ /dt
emf = -20 (0.0015) 0.51 / 1
emf = - 0.0153
so magnitude of the induced emf in the coil is 0.0153 V
Answer:
7. the ball with a mass of 8.0kg
8.1225 kg
9.4.2 kg-m/sec
10.15m/sec
11.0.001kgm/sec
