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zysi [14]
4 years ago
13

The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 28 ft2 . find the dimensions

of the rectangle.
Mathematics
1 answer:
Minchanka [31]4 years ago
6 0
Let the width = w.
Then the length is 3w - 5.
The area = LW = 28

w(3w - 5) = 28

3w^2 - 5w = 28

3w^2 - 5w - 28 = 0

(3w + 7)(w - 4) = 0

3w + 7 = 0 or w - 4 = 0

w = -7/3 or w = 4

The width of a rectangle cannot be a negative number, so we discard w = -7/3.

The width is 4 ft.
The length is 3w - 5 = 3(4) - 5 = 12 - 5 = 7
The length is 7 ft

Answer: The dimensions are length 7 ft and width 4 ft.
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Using the trigonometric mnemonic SOH CAH TOA, we know that cos or cosine is the ratio between the adjacent side and hypotenuse side.

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corey’s campus store has $4,000 of inventory on hand at the beginning of the month. during the month, the company buys $41,000 o
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If Corey’s campus store has $4,000 of inventory on hand at the beginning of the month. during the month, the company buys $41,000 of merchandise and sells merchandise that had cost $30,000. at the end of the month, $13,000 of inventory is on hand. how much shrinkage occurred during the month will be $2,000

Beginning inventory on hand $4,000

Add purchase $41,000

Cost of goods sold $45,000

Less Ending Merchandise sold ($30,000)

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Shrinkage $2,000

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Learn more here:

brainly.com/question/18685380

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