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s2008m [1.1K]
3 years ago
9

What does the ratio 1/5 to 1/2 equal to simplified

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0
\frac{1}{5} : \frac{1}{2}

= \frac{1}{5} ÷ \frac{1}{2}

= \frac{1}{5} × \frac{2}{1}

= \frac{2}{5}

= 2 : 5

Hence, the answer is 2 : 5
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Can someone please help me this is geometry I don’t understand I have like more than an hour trying to figure this but I cancele
Aleks04 [339]

Answer:

5, last option

Step-by-step explanation:

Sides to be calculated are equal as both are opposite same angles, are adjacent to common hypotenuse of right triangles

  • 3x+1=2x+6
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6 0
3 years ago
The nth term of a sequence is 6 - n work out the first three terms and the 20th term of the sequence.
timurjin [86]

Step-by-step explanation:

a_n=6-n

➜a_1=6-1

<h3>➜5</h3>

➜,a_2=6-2

<h3>➜4</h3>

➜a_3=6-3

<h3>➜3</h3>

➜a_20=6-20

<h3>➜-14</h3>
3 0
3 years ago
What is the composition of transformations mapping ABC to A'B'C"? The first transformation is The second transformation is AABC
spin [16.1K]

Answer:

The first Transition is a reflection over the line M

The second transition is a 180 degree rotation.

Step-by-step explanation:

3 0
3 years ago
Write an explicit formula for an, the nth term of the sequence 11,2,-7
abruzzese [7]

Answer:

a_{n} = 20 - 9n

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 2 - 11 = - 7 - 2 = - 9

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 11 and d = - 9 , then

a_{n} = 11 - 9(n - 1) = 11 - 9n + 9 = 20 - 9n

8 0
3 years ago
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levacccp [35]

Refer to the attached diagram for further a visual explanation. As per the given information, segments (AB) and (AD) are congruent. Moreover, segments (AC) and (AE) are also congreunt. One is also given that angles (<BAD) and (<EAC) are congruent. However, in order to prove the triangles (ABC) and (ADE) are congruent (using side-angle-side) congruence theorem, one needs to show that angles (<BAC) and (<DAE) are congruent. An easy way to do so is to write out angles (<BAC) and (<DAE) as the sum of two smaller angles:

<BAC = <BAD + <DAC

<DAE = <DAC + <EAC

Both angles share angle (DAC) in common, since angles (<EAC) and (BAD) are congruent, angles (<BAC) and (<DAE) must also be congruent.

Therefore triangles (ABC) and (ADE) are congruent by side-angle-side, thus sides (BC) and (DE) must also be congruent.

In summary:

AB = AD                                               Given

AC = AE                                               Given

<BAD = <EAC                                      Given

<DAC = <DAC                                     Reflexive

<BAC = <BAD + <DAC                       Parts-Whole Postulate

<DAE = <EAC + < DAC                       Parts-Whole Postulate

<BAC = <DAE                                      Transitivity

ABC = ADE                                          Side-Angle-Side

BC = DE                                               Corresponding parts of congruent triangles are congruent

5 0
3 years ago
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