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Marina86 [1]
3 years ago
12

HELP ASAP!!! IM BEING TIMED. Use synthetic division to test one potential root. Enter the numbers that complete the division pro

blem.

Mathematics
2 answers:
marissa [1.9K]3 years ago
6 0

Answer:

So a=-5,c=-5,b=1,c=-12

Step-by-step explanation:

In synthetic division, you add the columns inside the box, you multiply the number under the bar by the number outside to get the next number in the column.

Example

Divide x^3+10x^2-5x+1 by x+4.

-4 goes on the outside because  you are dividing by (x+4).

-4   |    1          10        -5        1

     |               -4       -24        116

     -------------------------------------

          1           6        -29        117

So your problem you have this setup:

-5  |   1       6           -7         -60

    |

     ---------------------------------------

This is enough information to figure out the letter's you have:

So your problem you have this setup:

-5  |   1       6           -7         -60

    |          -5          -5           60

     ---------------------------------------

        1         1         -12          0

So a=-5,c=-5,b=1,c=-12

Diano4ka-milaya [45]3 years ago
3 0

Step-by-step explanation:

1 * (-5) = -5     a = -5

6 + (-5) = 1      b = 1

1 * (-5 ) = -5     c = -5

-7 + -5 = -12     d = -12

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2 years ago
Which of these equations represents a line parallel to the line 2x + y = 6?
laila [671]

Answer:

D) y= -2X+1

Step-by-step explanation:

All of the lines are perpendicular to the line 2x+y=6 except for D) y= -2X+1.

8 0
3 years ago
Help please! the question is in the picture below for reference when answering! thank you so much!
stepan [7]

Answer:

x = -1

Step-by-step explanation:

AB + BC = AC = 28

the way from A to C goes through B.

so, the total way of A to C is the sum of the way from A to B and then from B to C.

=>

(5x + 10) + (2x + 25) = 28

7x + 35 = 28

7x = -7

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4 0
3 years ago
Read 2 more answers
Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.
dusya [7]

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

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5 0
2 years ago
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Solve for x <br> -2^2(-5x+10)=100
masha68 [24]

Answer:

x=7

Step-by-step explanation:

Hi there!

-2^2(-5x+10)=100

Solve -2^2:

-4(-5x+10)=100

Divide both sides by -4:

\displaystyle \frac{ -4(-5x+10)}{-4}=\frac{100}{-4} \\\\-5x+10=-25

Subtract 10 from both sides:

-5x+10-10=-25-10\\-5x=-35

Divide both sides by -5:

\displaystyle \frac{-5x}{-5} = \frac{-35}{-5} \\\\x=7

Therefore, x = 7.

I hope this helps!

3 0
3 years ago
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