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Ulleksa [173]
3 years ago
6

An object with an initial velocity of 3.0 m/s has a constant acceleration of 2.0 m/s2. When its speed is 19.0 m/s, how far has i

t traveled?
Physics
1 answer:
PolarNik [594]3 years ago
7 0
V2=(Vo)2+2aS
2aS=V2-(Vo)2
S=(V2-(Vo)2)/2a
S=(361-9)/2*2
S=352/4
S=88m

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A car is travelling at a speed of 30 m/s. It decelerates at a rate of 12 m/s^2. Calculate the time taken for the car to come to
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Answer:

The answer to your question is: t = 2.5 s

Explanation:

Data

vo = 30 m/s

a = -12 m/s2

t = ?

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Formula

vf = vo + at

Substitution

                              0 m/s = 30 + (-12)t

Solve it for t           -30 = -12t

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Applying Newton's Second Law of Motion, the acceleration of the ball is 16.8 m/s^2

<u>Given the following data:</u>

  • Mass = 0.5 kg
  • Acceleration due to gravity = 9.8 m/s^2
  • Upward force = 3.5 N.

To find ball's acceleration, we would apply Newton's Second Law of Motion:

First of all, we would determine the net force acting on the ball.

Net \; force = Upward\;force + Downward\;force

Downward\;force = 0.5 × 9.8

Downward force =  4.9 N

Net \; force = 3.5 + 4.9

Net force = 8.4 N

Mathematically, Newton's Second Law of Motion is given by this formula;

Acceleration = \frac{Net\;force}{Mass}\\\\Acceleration = \frac{8.4}{0.5}

<em>Acceleration = 16.8 </em>m/s^2<em />

Therefore, the acceleration of the ball is 16.8 m/s^2

Read more here: brainly.com/question/24029674

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