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3 years ago

6

An object with an initial velocity of 3.0 m/s has a constant acceleration of 2.0 m/s2. When its speed is 19.0 m/s, how far has i

t traveled?

1 answer:

PolarNik [594]3 years ago

7 0

V2=(Vo)2+2aS
2aS=V2-(Vo)2
S=(V2-(Vo)2)/2a
S=(361-9)/2*2
S=352/4
S=88m

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The bullet will strike the target placed in 324.0 m in the East in 0.45 seconds.

<u>Explanation:</u>

As we all know the epic relation between distance, speed and time; we cam easily estimate the time in which an object can reach to the destination or target.

As here in this case, we know the distance of the target and the velocity of a bullet exerted from a rifle given as follows,

Distance of the Target from the rifle edge = 324.0 m

Velocity of bullet exerted from the rifle = 720 m/s

Since we know that,

$\text {velocity}=\frac{\text {distance}}{\text {time}}$

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$\text {Time}=\frac{\text {distance}}{\text {velocity}}$

We can simply implement all the values in the formula and get the results i.e the time required by the bullet to hit the target. Since both the values are in S.I units measures, we don't need to change or convert any of them. Hence,

$\text { Time }=\frac{324}{75}=0.45 \text { seconds }$

Therefore, the bullet will hit the target in 0.45 seconds.

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3 years ago