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My name is Ann [436]
3 years ago
13

Please help!!

Physics
2 answers:
Luba_88 [7]3 years ago
8 0

Answer:

Bath CD jshchdhdhfhfhhfhd jpg de f for frr for gi Jhong GO by be jr jpg be

erastova [34]3 years ago
7 0

34 bc of the velocity of the arrow will come down with less dense

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How is budgeting different for most states than for the federal government?
meriva

There are three general kinds of state balanced budget requirements:

<span>The governor's proposed budget must be balanced (43 states and Puerto Rico).The budget the legislature passes must be balanced (39 states and Puerto Rico).<span>The budget must be balanced at the end of a fiscal year or biennium, so that no deficit can be carried forward (37 states and Puerto Rico).
</span></span><span>Nature of state balanced-budget requirements All the states except Vermont have a legal requirement of a balanced budget. Some are constitutional, some are statutory, and some have been derived by judicial decision from constitutional provisions about state indebtedness that do not, on their face, call for a balanced budget. The General Accounting Office has commented that "some balanced budget requirements are based on interpretations of state constitutions and statutes rather than on an explicit statement that the state must have a balanced budget."

hope that helped, please mark me as brainliest

</span>
5 0
3 years ago
A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?
Alisiya [41]

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

7 0
3 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
laila [671]

Answer:

1.45544 J

Explanation:

See attachment

5 0
3 years ago
Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges
Nostrana [21]

Answer:

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

E_1 = E_2

Let the position where net field is zero will lie at distance "r" from q1

\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}

now we will have

\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}

now square root both sides

\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}

now we have

\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1

so we have

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

8 0
3 years ago
I need someone that has a course hero subscription to help me I need all the pages
SVETLANKA909090 [29]

Answer:

So what's the answer???

Explanation:

8 0
3 years ago
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