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hjlf
2 years ago
6

Alice suffered a minor electrical shock as she switched on her bathroom light. She is concerned and wants to prevent it from hap

pening again.
What should Alice do to prevent getting an electrical shock again?
Physics
2 answers:
snow_tiger [21]2 years ago
7 0
Get a pull chord light switch installed in her bathroom by a qualified electrician asap. Meanwhile, keep hands as dry as possible, and try not to go near that switch until it's either been properly earthed, or whatever the problem actually is, and get qualified advice on what the problem is. Don't have wet feet either, and don't stand in puddles of water whilst operating - i she has to - the switch. 250V AC mains can be lethal, and at least painful.
SSSSS [86.1K]2 years ago
6 0

Explanation :

Prevention that must follow by Alice are as follows :

(1) The first way to solve any electrical problems is to turn off the main source of electricity in your home.

(2) The electric devices must be kept away from water and from any moisture.

(3) She should install GFCI i.e. Ground Fault Circuit Interrupters in her home. GFCI detects the leakage of current in the circuit.

(4)  When electric equipment fuses again and again. it is no longer only an accident - those are signs and symptoms that something is not going the right way.

These are some prevention that Alice must take in case of electric shock.

You might be interested in
About how much of Earth's water is available for humans to use?
lesya692 [45]

Answer:

0.3 %

Explanation:

Earth cleans and replenishes the water supply through the hydrologic cycle. The earth has an abundance of water, but unfortunately, only a small percentage, is even usable by people.

5 0
2 years ago
an electric current of 285.0 ma flows 674. milliseconds. Calculate the amount of electric charge transported. Be sure your answe
yulyashka [42]

Answer:

<em>The amount of electric charge transported = 0.192 C</em>

Explanation:

Electric Charge: This is defined as the product of electric current and time in an electric circuit, The S.I unit of electric charge is Coulombs (C)

Q = It..................... Equation 1

Where Q = Electric charge, I = electric current, t = time.

<em>Given:</em> I = 285 mA, t = 674 milliseconds.

<em>Conversion: (i) Convert from 285 mA to A = (285/1000) A = 0.285 A</em>

<em>       (ii) convert from 674 milliseconds to seconds = (674/1000) s = 0.674 s          </em>

Substituting these values into equation 1

Q = 0.285 × 0.674

<em>Q = 0.192 C</em>

<em>Therefore the amount of electric charge transported = 0.192 C</em>

<em></em>

<em></em>

5 0
2 years ago
Plsssss I need te answer quick​
jok3333 [9.3K]

Explanation:

reflection ... . .......

3 0
3 years ago
Read 2 more answers
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c
ohaa [14]

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

        Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

        m g h = ½ m v²

        v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

6 0
2 years ago
a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma
ad-work [718]

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) p is given by the following equation:

p=m.V

Where:

m=45 kg is the mass of the skater

V is the velocity

In this situation the skater has two values of momentum:

Initial momentum: p_{1}=m.V_{1}

Final momentum: p_{2}=m.V_{2}

Where:

V_{1}=3 m/s

V_{1}=5 m/s

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

p=p_{2}-p_{1}=m.V_{2}-m.V_{1}

p=m(V_{2}-V_{1})

p=45 kg(5 m/s - 3 m/s)

Finally:

p=90 kgm/s

4 0
3 years ago
Read 2 more answers
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