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hjlf
2 years ago
6

Alice suffered a minor electrical shock as she switched on her bathroom light. She is concerned and wants to prevent it from hap

pening again.
What should Alice do to prevent getting an electrical shock again?
Physics
2 answers:
snow_tiger [21]2 years ago
7 0
Get a pull chord light switch installed in her bathroom by a qualified electrician asap. Meanwhile, keep hands as dry as possible, and try not to go near that switch until it's either been properly earthed, or whatever the problem actually is, and get qualified advice on what the problem is. Don't have wet feet either, and don't stand in puddles of water whilst operating - i she has to - the switch. 250V AC mains can be lethal, and at least painful.
SSSSS [86.1K]2 years ago
6 0

Explanation :

Prevention that must follow by Alice are as follows :

(1) The first way to solve any electrical problems is to turn off the main source of electricity in your home.

(2) The electric devices must be kept away from water and from any moisture.

(3) She should install GFCI i.e. Ground Fault Circuit Interrupters in her home. GFCI detects the leakage of current in the circuit.

(4)  When electric equipment fuses again and again. it is no longer only an accident - those are signs and symptoms that something is not going the right way.

These are some prevention that Alice must take in case of electric shock.

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A ball is thrown vertically upwards with an initial velocity of 20.00 m/s. Neglecting air resistance, how long is the ball in th
algol [13]

Answer:

1) The greatest height attained by the ball equals 20.387 meters.

2) The time it takes for the ball to reach 15 meters approximately equals 1 second.

Explanation:

The greatest height will be attained when the ball stop's in the air and starts falling back to the earth.

thus using third equation of kinematics we obtain the height attained as

v^2=u^2+2as

where

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's' is the distance it covers

Thus for maximum height applying the values in the equation we get

0=20^{2}-2\times 9.81\times h\\\\\therefore h=\frac{20^{2}}{2\times 9.81}=20.387meters

Using the same equation we can find the speed of the ball when it reaches 15 meters of height as  

v^2=20^{2}-2\times 9.81\times 15\\\\v^{2}=105.7\\\\\therefore v=10.28m/s

the time it takes to reduce the velocity to this value can be found by first equation of kinematics as

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