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masha68 [24]
3 years ago
10

A 20 kg rover is located on Mars where the acceleration due to gravity is 3.7 m/s/s.

Physics
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

74N

Explanation:

force = mass * acceleration

force =  20 * 3.7

force = 74N

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vlada-n [284]

Answer:

Since strong nuclear forces involve only nuclear particles (not electrons, bonds, etc)  items 3 and 4 are eliminated.

Again item 2 refers to bonds between atoms and is eliminated.

This leaves only item 1.

Nuclear forces are very short range forces between components of the nucleus.

Weak nuclear forces are trillions of times smaller than strong forces.

Gravitational forces are much much smaller than the weak nuclear force.

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The alpha line in the balmer series of the hydrogen spectrum consists of light having a wavelength of 6.56. calculate the freque
guajiro [1.7K]
The alpha line in the Balmer series is the transition from n=3 to n=2 and with the wavelength of λ=656 nm = 6.56*10^-7 m. To get the frequency we need the formula: v=λ*f where v is the speed of light, λ is the wavelength and f is the frequency, or c=λ*f. c=3*10^8 m/s. To get the frequency: f=c/λ. Now we input the numbers: f=(3*10^8)/(6.56*10^-7)=4.57*10^14 Hz. So the frequency of the light from alpha line is f= 4.57*10^14 Hz. 
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3 years ago
Which part of the electromagnetic spectrum is divided into seven ranges of wavelengths and is the part visible to the human eye
oksano4ka [1.4K]
In one of the most amazing coincidences in all of science,
the part of the electromagnetic spectrum that's visible to the
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Visible light is not 'divided' into anything. We mention the names
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6 0
3 years ago
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A metal pot feels hot to the touch after a short time on the shove. what type of material is the metal pot
Morgarella [4.7K]
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3 years ago
A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.75 m/s. If the roof is pitched at
dalvyx [7]

Answer:

a) t = 0.528 s

b) D = 1.62 m

Explanation:

given,

speed of the baseball = 3.75 m/s

angle made with the horizontal = 35°

height of the roof edge = 2.5 m

using equation of motion

s = ut +\dfrac{1}{2}gt^2

2.5 = vsin\theta \ t +\dfrac{1}{2}gt^2

2.5 = 3.75\ sin35^0 \ t +\dfrac{1}{2}\times 9.8 t^2

4.9 t² + 2.15 t - 2.5 = 0

on solving the above equation

t = 0.528 s

b) D = v cos θ × t

D = 3.75 × cos 35° ×0.528

D = 1.62 m

3 0
4 years ago
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