At 1.70 atm, a gas sample occupies 4.25 liters. If the pressure in the gas increases to 2.40 atm, what will the new volume be?
Answer:
3.01L
Explanation:
Given parameters:
Initial pressure, P1 = 1.7atm
Initial volume, V1 = 4.25L
Final pressure, P2 = 2.4atm
Unknown:
Final or new volume, V2 = ?
Solution:
To solve this problem, we use Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".
P1 V1 = P2 V2
P1 is the initial pressure
V1 is the initial volume
P2 final pressure
V2 final volume
1.7 x 4.25 = 2.4 x V2
V2 = 3.01L
pavement is defined as the surface of Road or sidewalk.
for example, the surface of Expressway.
There are two types of pavement.
rigid pavement which consists of one layer.
flexible pavement which consist of multiple layers.
While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the pedal, then apply brake lightly until we are moving at a low speed.
if you run off the pavement, you should: turn the steering wheel quickly toward the road steer straight and slow down before attempting to return to the pavement steer straight ahead and speed up apply the brakes hard
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If the separation between the openings in a laser is increased, then the distance between the interference fringes decreases
<h3>What is Interference fringe ?</h3>
Interference fringe refers to bands caused by different lights which can be found in phase or not each other.
- Distances between laser fringes are short which is due to light wavelength.
- The interference fringes can be estimated by knowing slit separation and wavelength.
In conclusion, if the separation between the openings in a laser is increased, then the distance between the interference fringe decreases
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Answer is b that is Heat energy from below the ground converts water to steam to drive a steam turbine attached to an electrical generator.. .
Answer
given,
wavelength (λ)= 500 n m
thickness of film= 10⁻⁴ cm
refractive index = μ = 1.375
distance traveled is double which is equal to 2 x 10⁻⁴ cm
a) Number of wave


N = 2.91
N = 3
b) phase difference is equal to
Reflection from the first surface has a 180° (½λ) phase change.
There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.
net phase difference = 
= 270°