Answer:
The acceleration of the train must be - 0.133 m/s²
Explanation:
Lets explain how to solve the problem
A train in order for it to stop 12 m/s in a distance if 541 m
That means the initial velocity of the train is 12 m/s
Its final velocity is zero (stop)
The distance it covers is 541 m
We want to find its acceleration
The acceleration will be negative quantity because the train reduced its
velocity from 12 m/s to zero
We need rule contains velocity, acceleration and distance
So we will use ⇒<em> v² = u² + 2as</em>, where v is the final velocity, u is the
initial velocity, a is the acceleration and s is the distance
v = 0, u = 12 m/s, s = 541 m
Substitute these values in the rule
(0)² = (12)² + 2(a)(541)
0 = 144 + 1082 a
Subtract 144 from both sides
-144 = 1082 a
Divide both sides by 1082
- 0.133 = a
<em>The acceleration of the train must be - 0.133 m/s²</em>
