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Drupady [299]
3 years ago
7

angelina has 5 cakes. She wants to cut them into 1/5 pieces. How many pieces will she be able to cut??

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

25 pieces

Step-by-step explanation:

If she has 5 cakes, and she wants 5 pieces from each cake, simply multiply 5 times 5 to get 25 pieces of cake.

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Gekata [30.6K]

Answer:

1. A $28.18

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2 years ago
Pls and step by step
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Step-by-step explanation:

90+75=135

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2 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
8n + 12 - 5n = 21<br> n=?
insens350 [35]

Answer:

n=3

Step-by-step explanation:

Simplifying

8n + 12 + -5n = 21

Reorder the terms:

12 + 8n + -5n = 21

Combine like terms: 8n + -5n = 3n

12 + 3n = 21

Solving

12 + 3n = 21

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.

12 + -12 + 3n = 21 + -12

Combine like terms: 12 + -12 = 0

0 + 3n = 21 + -12

3n = 21 + -12

Combine like terms: 21 + -12 = 9

3n = 9

Divide each side by '3'.

n = 3

Simplifying

n = 3

5 0
3 years ago
Read 2 more answers
If a rectangular prism is sliced vertically by a plane, what is the shape of the resulting two dimensional figure?
Romashka [77]
I think 2 triangular prisms.
8 0
3 years ago
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