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MArishka [77]
4 years ago
11

Two triangles have side lengths 3, 4, 5 and 6, 8, 10, respectively. The triangles are similar to each other.

Mathematics
1 answer:
artcher [175]4 years ago
8 0
Haha, you see your first triangle is 3,4,5 and the next is 6,8,10 the second triangle is twice as big as the first one! 3+3=6 4+4=8 and 5+5=10 there just doubled.
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50 – 5(4.3 – 1.3) ÷ 0.5
marissa [1.9K]

Answer:

(0.5, 1.3)(0.5, 1.3)

Step-by-step explanation:

Given equations are:

As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)

We can see from the graph that the lines intersect at: (0.517, 1.267)

Rounding off both coordinates of point of intersection to nearest tenth we get

(0.5, 1.3)

Hence,

(0.5, 1.3) is the correct answer

Keywords: Linear equations, variables

4 0
3 years ago
Read 2 more answers
Given Angle 1 =xº and angle 2 = (x +50)°.<br> Find the value of x. Then find angle 1 and 2
Elis [28]

Answer:

x=65

Angle 1=65

Angle 2=115

Step-by-step explanation:

We know that angle 1 + angle 2 = 180. Writing it in terms of x, we get x + (x + 50)= 180. Then you have 2x+50=180. Subtracting 50 from both sides gives you 2x=130. Dividing both sides by 2, you get x=65. Angle 1 is 65 degrees. 180-65=115.

6 0
3 years ago
A gardener is testing various values of x for a rectangular garden with length 2x + 5 meters and width x – 3 meters. The product
vlabodo [156]
This is one of those questions where there's a list of choices that goes along with it,
but you're not sharing the list.

The product of (2x + 5) and (x - 3) is (2x² - x - 15) . That may be useful.
6 0
4 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
4 years ago
For every increase of one on the Richter scale, an earthquake is ten times more powerful. Which of the following models this sit
Goshia [24]

Answer:

Step-by-step explanation:

exponential growth function

8 0
3 years ago
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