What is the si unit for heat

The figure shows a graph of Allison’s walk to school. She follows the black vectors to get to her school. Which if the following

Lubov Fominskaja [6]

Answer:

Allison walks 5 blocks west and 3 blocks south.

Explanation:

Vectors have both magnitude and direction. The attached figure shows the graph of Allison’s walk to school. She follows the black vectors to get to her school.

The first vector on the horizontal axis points towards west and there are 5 blocks. Initially, she walks 5 blocks in west direction.

The second vector points in the negative vertical axis. It means that she walks 3 block in south direction.

Hence, the correct option is (D) i.e. Allison walks 5 blocks west and 3 blocks south.

7 0

3 years ago

A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *

elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

P1 = initial pressure (kPa)
P2 = final pressure (kPa)
V1 = initial volume (L)
V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0

3 years ago

HELP ASAP PLZ!!! WILL GIVE BRAINLIEST

Illusion [34]

Answer:

A diamond is a pure substance because it is made of one element.

Explanation:

From the crystalline structure model of the diamond, we can see that we only have just one element represented by the green balls connected in a cross linked fashion to one another. Therefore, one can rightly conclude that this is a pure substance made up of one element.

In a pure substance, all parts are homogeneous and composition is definite.

3 0

3 years ago

1. How many grams of B are present in 3.35 grams of boron tribromide ?

Andre45 [30]

Answer:

The answer to your question is:

Explanation:

1. How many grams of B are present in 3.35 grams of boron tribromide ?

________ grams B.

MW BBr₃ = 251 g

251 g of BBr₃ ---------------------- 11 g of B

3.35 g ----------------------- x

x = (3.35 x 11) / 251 = 0.147 g of B

2. How many grams of boron tribromide contain 4.69 grams of Br ?

________grams boron tribromide.

MW BBr₃ = 251g

251g of BBr₃ ----------------- 80 g of Br

x ----------------- 4.69 g

x = (4.69 x 251)/ 80 = 14.71 g of BBr₃

3. How many grams of N are present in 4.11 grams of nitrogen trifluoride ?

________grams N.

MW NF₃ = 71 g

71 g of NF₃ ----------------- 14 g of N

4.11 g ---------------- x

x = (4.11 x 14) / 71 = 0.81 g of N

4. How many grams of nitrogen trifluoride contain 3.07 grams of F ?

________grams nitrogen trifluoride.

MW NF₃ = 71

71 g of NF₃ --------------------- 19 g of F

x --------------------- 3.07 g

x = (3.07 x 71) / 19 = 11.5 g of NF₃

5.How many grams of Co3+ are present in 1.16 grams of cobalt(III) iodide?

________grams Co3+.

MW CoI₃ = 440 g

440 g of CoI₃ ------------------ 59 g of Co

1.16 g ------------------ x

x = (1.16 x 59) / 440 = 0.16 g of Co

6. How many grams of cobalt(III) iodide contain 2.28 grams of Co3+?

________grams cobalt(III) iodide.

MW CoI₃ = 440 g

440 g of CoI₃ ------------------ 59 g of Co

x ----------------- 2.28 g of Co⁺³

x = (2.28 x 440) / 59

x = 17 g of CoI₃

5 0

3 years ago

What is the energy change that will occur when 25.5 grams of oxygen gas (O2) react with excess methane (CH4) according to the re

AysviL [449]

Amount of CH4 is excess, so no need to worry about it
but the limiting factor is the Oxygen 

according to stranded equation, 

CH4 + 2 O2 --> CO2 + 2 H2O ΔH = -889 kJ/mol 

just by taking proportions 

(-889 kJ/mol) / 2 x 0.8 mol = - 355.6 kJ 

so i think the answer is (a)

7 0

3 years ago