Answer:
decelerating hope this helps❤️
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Answer:</h3>
#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂
#2. Type of reaction: Synthesis reaction
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Explanation:</h3>
- Balanced equations are equations that obey the law of conservation of mass.
- When an equation is balanced the number of atoms of each element is equal on both side of the equation.
- Equations are balanced by putting appropriate coefficients on the reactants and products.
- In our case, we are going to put coefficients 2, 1 and 1.
- Thus, the balanced equation will be;
2C₅H₅ + Fe → Fe(C₅H₅)₂
- This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.
The answer is- 
is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.
Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.
Determine the molecular geometry of .
- Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
- According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
- Now, calculate the total number of valence electrons in .
Valence electrons of S = 6
Valence electrons of F = 7
Thus, the valence electrons in are-
- The Lewis structure of is - (Image attached).
- In the structure, the number of atoms bonded to central atom (S) = 6.
- Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
- Electronic geometry in case of 6 bond pairs is octahedral.
- Molecular geometry us also octahedral with bond angles 90°.
- Central atom is sp3d2 hybridised.
- is a non-polar molecule.
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Answer:
See explanation
Explanation:
Qualitative analysis in chemistry is a method used to determine the ions present in a solution chiefly by means of chemical reactions.
In this case, I suspect the presence of silver ions and/or barium ions. The first step is to add dilute HCl. This will lead to the precipitation of the silver ion as AgCl. If a white precipitate is formed upon addition of HCl then Ag^+ is present in the solution.
Secondly, I add a carbonate such as NH4CO3(aq). This will cause the barium ions to become precipitated as barium carbonate. Hence, the formation of a white precipitate when NH4CO3(aq) is added to the solution indicates the presence of barium ion in the solution.
