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3 years ago

Which of the following materials could have been found in the giant cloud that formed the

Chemistry

1 answer:

Natalija [7]3 years ago

4 0

Hydrogen and helium

These are the lightest atoms in the universe and are at the top-most of the periodic table.

Explanation:

These hydrogen and helium gas clouds when the collapse due to their own gravity, begin to fuses producing fusion energy that form stars. These light atoms become fused into heavier atoms in the center of these stars. When hydrogen and helium are fused, they form heavier atoms like those of carbon and oxygen. Supermassive stars, with intense gravity, will fuse even the heavier atoms like carbon into even heavier elements like Iron.

Learn More:

For more on fusion check out;

brainly.com/question/11498700

brainly.com/question/12201864

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An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

djverab [1.8K]

Answer:

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=P_1=13.2 Torr$

Partial pressure of the $Cl_2=P_2=13.2 Torr$

Partial pressure of the $PCl_5=P_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{P_1}{P_1\times P_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=P_1'=13.2 Torr$

Partial pressure of the $Cl_2=P_2'=?$

Partial pressure of the $PCl_5=P_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=P_1'+P_2'+P_3'$

$263.0Torr=13.2 Torr+P_2'+217.0 Torr$

$P_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{P_3'}{P_1'\times P_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

5 0

2 years ago

wich answer choice contains organisms that are all prokaryotic. A. archaebacteria and bacteria B. bacteria and fungi C. protists

JulijaS [17]

Answer:

Explanation:

6 0

2 years ago

Read the statements. In eukaryotic organisms, genes usually consist of two alleles. The two alleles are often on different parts

lina2011 [118]

Answer:

I think its B but im not too sure

5 0

1 year ago

Is elemental phosphorus dull or high luster?

Ugo [173]

Each element can usually be classified as a metal or a non-metal based on their ... They are usually dulland therefore show no metallic luster and they do not reflect ... Dull, Brittle solids; Little or no metallic luster; High ionization energies; High ...

7 0

3 years ago

The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes su

masha68 [24]

Answer:

The correct answer is "-268.667°C".

Explanation:

Given:

Temperature,

= 4.483 K (below)

Now,

The formula of temperature conversion will be:

⇒ $T(^{\circ} C)=T(K)-273.15$

By putting the values, we get

⇒ $=4.483-273.15$

⇒ $=-268.667^{\circ} C$

Thus the above is the correct answer.

3 0

2 years ago