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Olegator [25]
3 years ago
10

The following reaction has been reported in the chemical literature and gives a single organic product in high yield. Write the

structure of the product for the reaction of styrene with bromine in aqueous solution (ignore stereochemistry).
(a) 2-phenylpropene + HCl
(b) Styrene + Beomin in aqueous solution

Chemistry
1 answer:
Alla [95]3 years ago
8 0

Answer:

Explanation:

The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.

In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.

The reaction and the structure of the product is as shown in the attachment.

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1. element with three occupied energy levels and<br> one valence electron
vfiekz [6]

Answer:

Potassium (K) = (2,8,8,1)

This is the element that has three(3) filled energy level and one valence electron

3 0
3 years ago
Eric's father asked an engineer to survey the field behind their house. He wanted to plant some apple and pear trees there. Acco
Vsevolod [243]

Answer:

11,000 cm

Explanation:

Step 1: Given data

Width of the field (w): 17 meters

Length of the field (l): 38 meters

Step 2: Calculate the perimeter of the field

The field is a rectangle. We can find its perimeter (P) by adding its sides.

P = 2 × w + 2 × l = 2 × 17 m + 2 × 38 m = 110 m

Step 3: Convert the perimeter to centimeters

We will use the relationship 1 m = 100 cm.

110 m × (100 cm/1 m) = 11,000 cm

8 0
3 years ago
समश्याजिक क्या है हाइड्रोजन का समस्थानिय<br>को समपस्य?​
LUCKY_DIMON [66]

Answer:

GO

Explanation:

8 0
3 years ago
Carvone (C10H14O) is the main component of spearmint oil. It has a pleasant aroma and mint flavor. Carvone is often added to che
marta [7]

<u>Answer:</u> The mass of carbon in given amount of carvone is 47.52 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of carvone = 55.4 g

Molar mass of carvone = 150.22 g/mol

Putting values in equation 1, we get:

\text{Moles of carvone}=\frac{55.4g}{150.22g/mol}=0.369mol

The chemical formula of carvone is C_{10}H_{14}O

This contains 10 moles of carbon atom, 14 moles of hydrogen atom and 1 mole  of oxygen atom

Now, calculating the mass of carbon in carvone from equation 1, we get:

Molar mass of carbon = 12 g/mol

Moles of carbon = (10 × 0.396) = 3.96 moles

Putting values in equation 1, we get:

3.96mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=(3.96mol\times 12g/mol)=47.52g

Hence, the mass of carbon in given amount of carvone is 47.52 grams

6 0
3 years ago
The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process.... In the first step, manganes
frez [133]

Answer : The mass of MnCO_3 required are, 35 kg

Explanation :

First we have to calculate the mass of MnO_2.

The first step balanced chemical reaction is:

2MnCO_3+O_2\rightarrow 2MnO_2+2CO_2

Molar mass of MnCO_3 = 115 g/mole

Molar mass of MnO_2 = 87 g/mole

Let the mass of MnCO_3 be, 'x' grams.

From the balanced reaction, we conclude that

As, (2\times 115)g of MnCO_3 react to give (2\times 87)g of MnO_2

So, xg of MnCO_3 react to give \frac{(2\times 87)g}{(2\times 115)g}\times x=0.757xg of MnO_2

And as we are given that the yield produced from the first step is, 65 % that means,

60\% \text{ of }0.757xg=\frac{60}{100}\times 0.757x=0.4542xg

The mass of MnO_2 obtained = 0.4542x g

Now we have to calculate the mass of Mn.

The second step balanced chemical reaction is:

3MnO_2+4Al\rightarrow 3Mn+2Al_2O_3

Molar mass of MnO_2 = 87 g/mole

Molar mass of Mn = 55 g/mole

From the balanced reaction, we conclude that

As, (3\times 87)g of MnO_2 react to give (3\times 55)g of Mn

So, 0.4542xg of MnO_2 react to give \frac{(3\times 55)g}{(3\times 87)g}\times 0.4542x=0.287xg of Mn

And as we are given that the yield produced from the second step is, 80 % that means,

80\% \text{ of }0.287xg=\frac{80}{100}\times 0.287x=0.2296xg

The mass of Mn obtained = 0.2296x g

The given mass of Mn = 8.0 kg = 8000 g     (1 kg = 1000 g)

So, 0.2296x = 8000

x = 34843.20 g = 34.84 kg = 35 kg

Therefore, the mass of MnCO_3 required are, 35 kg

4 0
3 years ago
Read 2 more answers
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