Answer:
d = 43.5 g/cm³
Explanation:
Given data:
Mass of magnesium cube = 217.501 g
Volume of magnesium cube = 5.00 cm³
Density of magnesium cube = ?
Solution:
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
d = 217.501 g/ 5.00 cm³
d = 43.5 g/cm³
Mass of KCl= 19.57 g
<h3>Further explanation</h3>
Given
12.6 g of Oxygen
Required
mass of KCl
Solution
Reaction
2KClO3 ⇒ 2KCl + 3O2
mol O2 :
= mass : MW
= 12.6 : 32 g/mol
= 0.39375
From the equation, mol KCl :
= 2/3 x mol O2
= 2/3 x 0.39375
=0.2625
Mass KCl :
= mol x MW
= 0.2625 x 74,5513 g/mol
= 19.57 g
Answer:
Aluminum , iron , gold , silver , nickels etc are the type of elements form metallic bonds .
The compound with a chemical formula of C₃H₈ is propane. The subscripts actually represent the number of the individual atoms in 1 particle of the compound. Since there are the same number of atoms per mole of any substance, the subscript can also represent the moles. Through stoichiometric calculations, the solution is as follows:
Moles of Carbon = 11.2 moles H * 3 mol C/8 mol H = <em>4.2 moles</em>
Answer:
The initial temperature of helium was T1 = 232.23 K
Explanation:
Given data:
Initial volume V1 = 5 L
Initial pressure P1 = 699 mmHg
Final pressure P2 = 800 mmHg
Final volume V2 = 5.7 L
Final temperature T2= 303 K
Initial temperature T1 = ?
Solution:
Formula:
P1V1/T1 = P2V2/T2
T1 = T2 × P1V1/P2V2
T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L
T1 = 1058985/ 4560
T1 = 232.23 K
initial temperature of helium was 232.23 k.
