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3 years ago

Which type of rock forms as a result of cooling and crystallization?

Chemistry

1 answer:

Dovator [93]3 years ago

7 0

Answer:

Igneous rock is the type of rock that forms as a result of cooling an crystallization

Explanation:

Rocks are either sedimentary, igneous or metamorphic based on the chemical composition and the mode of formation.
Igneous rocks are formed as a result of the cooling and crystallization of magma from volcanic eruptions.
Igneous rocks are either intrusive, which form deep in the crust or extrusive which form on the surface of the earth.
Sedimentary rocks are formed as a result of deposition, and cementation of sediments.
Metamorphic rocks, on the other hand, are formed from the sedimentary and igneous rocks during the rock cycle.

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Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held

Cerrena [4.2K]

Answer : The heat energy absorbed will be, $1.23\times 10^5cal$

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(32.0^oC)$

The expression used will be:

$\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]$

where,

m = mass of ice = 1100 g

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$\Delta H_{fusion}$ = enthalpy change for fusion = $6.01kJ/mole=6010J/mole=\frac{6010J/mole}{18g/mole}J/g=333.89J/g$

Molar mass of water = 18 g/mole

Now put all the given values in the above expression, we get:

$\Delta H=1100g\times 333.89J/g+[1100g\times 4.18J/g^oC\times (32.0-0)^oC]$

$\Delta H=514415J=122948.1358cal=1.23\times 10^5cal$

Conversion used : (1 cal = 4.184 J)

Therefore, the heat energy absorbed will be, $1.23\times 10^5cal$

7 0

3 years ago

A student notices that after two chemicals are mixed together the temperature of the mixture is higher than the temperature of t

swat32

Answer: exothermic

EXPLANATION: any process in which heat energy is released is called an exothermic process. For example burning of wood produces heat, so combustion of wood is an exothermic process.

When chemicals were not mixed they were at room temperature and when we mix them exothermic reaction took place and heat was released which raised the temperature of mixture.

7 0

3 years ago

In the laboratory, hydrogen gas is usually made by the following reaction: Zn(s) + 2 HCl(aq) → H2(g) + ZnCl2(aq) How many liters

IrinaK [193]

<u>Answer:</u> The volume of hydrogen gas collected over water is 2.13 L

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of zinc = 5.566 g

Molar mass of zinc = 65.4 g/mol

Putting values in above equation, we get:

$\text{Moles of zinc}=\frac{5.566g}{65.4g/mol}=0.0851mol$

For the given chemical reaction:

$Zn(s)+2HCl(aq.)\rightarrow H_2(g)+ZnCl_2(aq.)$

As, HCl is present in excess. So, it is considered as an excess reagent.

Zinc is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of zinc produces 1 mole of hydrogen gas.

So, 0.0851 moles of zinc will produce = $\frac{1}[1}\times 0.0851=0.0851mol$ of hydrogen gas

To calculate the volume of hydrogen gas, we use ideal gas equation, which is:

PV = nRT

where,

P = Pressure of hydrogen gas = Total atmospheric pressure - vapor pressure of water = (752 - 18.65) mmHg = 733.35 mmHg

V = Volume of the hydrogen gas

n = number of moles of gas = 0.0851 moles

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

T = Temperature of hydrogen gas = $21^oC=[21+273]K=294K$

Putting values in above equation, we get:

$733.35mmHg\times V=0.0851mol\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 294K\\\\V=\frac{0.0851\times 62.3637\times 294}{733.35}=2.13L$

Hence, the volume of hydrogen gas collected over water is 2.13 L

5 0

3 years ago

What is the threshold frequency ν0 of cesium?

Montano1993 [528]

I think this is what you're after:

Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1]

Convert to J and divide by the Avogadro Const to give E in J per photon

E = 375700/6.022×10^23 = 6.239×10^-19 J

Plank relationship E = h×ν E in J ν = frequency (Hz s-1)

Planck constant h = 6.626×10^-34 J s

6.239×10^-19 = (6.626×10^-34)ν

ν = 9.42×10^14 s^-1 (Hz)

IP are usually given in ev Cs 3.894 eV

<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>

4 0

3 years ago

Given the following equation: Cu + 2 AgNO3 ---> Cu(NO3)2 + 2

Temka [501]

Given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

<h3>How to calculate mass of substances?</h3>

The mass of a substance can be calculated using the following steps:

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

1 mole of Cu react with 2 moles of AgNO3

Molar mass of AgNO3 = 169.87 g/mol
Molar mass of Cu = 63.5g/mol

moles of AgNO3 = 262g/169.87g/mol = 1.54mol

1.54 moles of AgNO3 will react with 0.77 moles of Cu.

mass of Cu = 0.77 × 63.5 = 48.97g

Therefore, given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

Learn more about mass at: brainly.com/question/6876669

8 0

2 years ago