In addition to bandages and gauze, it's recommended that a first aid kit also contain
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Answer:
(a) Current density at P is .
(b) Total current I is 3.257 A
Explanation:
Because question includes symbols and formulas it can be misunderstood. In the question current density is given as below;
where and
unit vectors.
(a) In order to find the current density at a specific point <em>(P)</em>, we can simply replace the coordinates in the current density equation. Therefore
(b) Total current flowing outward can be calculated by using the relation,
where integral is calculated through the circular band given in the question. We can write the integral as below,
due to unit vector multiplication. Then,
where . Therefore
Answer:
Frequency = 3.5294×10¹⁴ s⁻¹
Wavenumber = 1.1765×10⁶ m⁻¹
Energy = 2.3365x 10⁻¹⁹ J , 1.4579 eV , 2.3365x 10⁻¹² erg
Explanation:
Given the wavelength = 850 nm
1 nm = 10⁻⁹ m
So, wavelength is 850×10⁻⁹ m
The relation between frequency and wavelength is shown below as:
c = frequency × Wavelength
Where, c is the speed of light having value = 3×10⁸ m/s
So, Frequency is:
Frequency = c / Wavelength
Frequency = 3.5294×10¹⁴ s⁻¹
Wavenumber is the reciprocal of wavelength.
So,
Wavenumber = 1 / Wavelength = 1 / 850×10⁻⁹ m
Wavenumber = 1.1765×10⁶ m⁻¹
Also,
where, h is Plank's constant having value as 6.62x 10⁻³⁴ J.s
So,
Energy = 6.62x 10⁻³⁴ J.s × 3.5294×10¹⁴ s⁻¹
Energy = 2.3365x 10⁻¹⁹ J
Also,
1 J = 6.24×10¹⁸ eV
So,
Energy = 2.3365x 10⁻¹⁹ × 6.24×10¹⁸ eV
Energy = 1.4579 eV
Also,
1 J = 10⁷ erg
So,
Energy = 2.3365x 10⁻¹⁹ × 10⁷ erg
Energy = 2.3365x 10⁻¹² erg
Answer:
the required expression is = 4[ 1 -
]
Explanation:
Given the data in the question;
Q = -0.2[ 1 - ]
ω = 100 rad/s
Torque T = 18 N-m
Electric power input = 2.0 kW
now, form the first law of thermodynamics;
dE/dt = dQ/dt + dw/dt = Q' + w'
dE/dt = Q' + w' ------ let this be equation 1
w' is the net power on the system
w' = -
= T × ω
we substitute
= 18 × 100
= 1800 W
= 1.8 kW
so
w' = -
w' = 2.0 kW - 1.8 kW
w' = 0.2 kW
hence, from equation 1, dE/dt = Q' + w'
we substitute
dE/dt = -0.2[ 1 - ] + 0.2
dE/dt = -0.2 + 0.2 ] + 0.2
dE/dt = 0.2
Now, the change in total energy, increment E, as a function of time;
ΔE =
ΔE =
ΔE =
= 4[ 1 -
]
Therefore, the required expression is = 4[ 1 -
]