Answer:
A job hazard analysis is a technique that focuses on job tasks as a way to identify hazards before they occur. It focuses on the relationship between the worker, the task, the tools, and the work environment. After uncontrolled hazards are identified, take action to eliminate them or reduce risk.
Complete Question:
Find the capacitive reactance of a 0.1 microfarad capacitor with frequency 50Hz and at 200Hz.
Answer:
I. Capacitive reactance = 31826.86 Ohms.
II. Capacitive reactance = 7956.72 Ohms.
Explanation:
<u>Given the following data;</u>
Capacitance = 0.1 uF = 0.0000001 Farad
Frequency = 50 Hz and 200 Hz
To find the capacitive reactance;
Mathematically, the capacitive reactance of an electronic circuit is given by the formula;

Where;
- Xc is capacitive reactance.
- f is the frequency.
- c is the capacitance.
Substituting into the formula, we have;
I. At frequency, f = 50 Hz




II. At frequency, f = 200 Hz




Answer:
Explanation:
It is the voltage a voltmeter would read when connected across something that has resistance.
___________0_________O______O_______
| |
| | |
|_____________________| |_____________ |
|
The diagram above is supposed to represent 3 lightbulbs connected in series. The vertical lines in the middle are supposed to be a battery which powers the three light bulbs. If you put a voltmeter across one of the lightbulbs, it will read a voltage that is 1/3 of the voltage of the battery.
Answer
That reading you get across the one light bulb is The Voltage Drop.
Answer:
Explanation:
Given:
Tooth Number, N = 24
Diametral pitch pd = 12
pitch diameter, d = N/pd = 24/12 = 2in
circular pitch, pc = π/pd = 3.142/12 = 0.2618in
Addendum, a = 1/pd = 1/12 =0.08333in
Dedendum, b = 1.25/pd = 0.10417in
Tooth thickness, t = 0.5pc = 0,5 * 0.2618 = 0.1309in
Clearance, c = 0.25/pd = 0.25/12 = 0.02083in