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Zolol [24]
3 years ago
7

What is the first step in the problem-solving process, as well as in the engineering design process?

Engineering
1 answer:
DENIUS [597]3 years ago
5 0

Answer:

C. Brainstorm

Explanation:

<em>Brainstorming refers to thinking and developing ideas and solutions to problems</em>. It involves a free-thinking approach and putting oneself in the context of the problem you are attempting to solve. You can use the empathy maps to combine ideas from interviewing other people on the same. This stage is followed by defining the problem, concept generation, developing a solution, constructing a testing a prototype, evaluating the solution and finally presenting the solution.

Answer choice A is incorrect because it is the last stage .

Answer choice B is incorrect because it is the second stage.

Answer choice D is incorrect because it is step 5 and 6.

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What does it take to launch a rocket in space?
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To get rockets into orbit, they need much more thrust than the amount that will get them up to the required altitude. They also need sufficient thrust to allow them to travel with very high orbital speed. ... If speed is less than this, an object will fall back to the Earth
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3 years ago
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Consider an aircraft powered by a turbojet engine that has a pressure ratio of 9. The aircraft is stationary on the ground, held
77julia77 [94]

Answer:

The break force that must be applied to hold the plane stationary is 12597.4 N

Explanation:

p₁ = p₂, T₁ = T₂

\dfrac{T_{2}}{T_{1}} = \left (\dfrac{P_{2}}{P_{1}}  \right )^{\frac{K-1}{k} }

{T_{2}}{} = T_{1} \times \left (\dfrac{P_{2}}{P_{1}}  \right )^{\frac{K-1}{k} } = 280.15 \times \left (9  \right )^{\frac{1.333-1}{1.333} } = 485.03\ K

The heat supplied = \dot {m}_f × Heating value of jet fuel

The heat supplied = 0.5 kg/s × 42,700 kJ/kg = 21,350 kJ/s

The heat supplied = \dot m · c_p(T_3 - T_2)

\dot m = 20 kg/s

The heat supplied = 20*c_p(T_3 - T_2) = 21,350 kJ/s

c_p = 1.15 kJ/kg

T₃ = 21,350/(1.15*20) + 485.03 = 1413.3 K

p₂ = p₁ × p₂/p₁ = 95×9 = 855 kPa

p₃ = p₂ = 855 kPa

T₃ - T₄ = T₂ - T₁ = 485.03 - 280.15 = 204.88 K

T₄ = 1413.3 - 204.88 = 1208.42 K

\dfrac{T_5}{T_4}  = \dfrac{2}{1.333 + 1}

T₅ = 1208.42*(2/2.333) = 1035.94 K

C_j = \sqrt{\gamma \times R \times T_5} = √(1.333*287.3*1035.94) = 629.87 m/s

The total thrust = \dot m × C_j = 20*629.87 = 12597.4 N

Therefore;

The break force that must be applied to hold the plane stationary = 12597.4 N.

5 0
2 years ago
How does a rudder help maneuver an airplane?
Nonamiya [84]
It’s just helps it like
4 0
2 years ago
Why can you anodise Aluminium and Magnesium alloys?
Anastasy [175]

Explanation:

Anodizing :

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As the name stand that in the anodizing process there will be anode and oxygen.in this process oxidation of material take place .

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4 0
3 years ago
Describe the greatest power in design according to Aravena?
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I got all three answers

4 0
2 years ago
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