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3 years ago

7 seres vivos ejemplo

Chemistry

1 answer:

vredina [299]3 years ago

4 0

7 seres vivos ejemplo means live example series in English!

Hope this helpED!!!️️️

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Do you think a battery system would OR wouldn’t have energy? If so, give me evidence/observations as to why you think so.

Basile [38]

Answer:

Yes it would

Explanation: Well it kinda depend on the voltage and how the battery has been in use or based on the condition

6 0

3 years ago

385 J of heat are needed to heat a piece of aluminum from 22°C to 45°C. If the specific heat of Al is 0.90 J/g°C, what is the ma

VikaD [51]

Answer:

M of Al=33.09g or 0.0331kg

Explanation:

Heat Energy= specific heat*mass*change in temperature

H=M*C*T

make M subject of the formula

M=H/CT

M=685J/0.90J/g°C*(45°C-22°C)

M=685J/0.90J/g°C*23°C

M=685J/20.7J/g

M=33.09g or 0.0331kg

4 0

3 years ago

3Fe+4H2O(yields) Fe3O4+4H2. What is the mole ratio of Fe3O4 to Fe?

WINSTONCH [101]

Answer: The correct answer is Option A.

Explanation:

Mole ratio is defined as the ratio between the stoichiometric coefficients of the molecules present in the chemical reaction.

For the given balanced chemical equation:

$3Fe+4H_2O\rightarrow Fe_3O_4+4H_2$

By Stoichiometry of the reaction:

3 moles of iron metal reacts with 4 moles of water to produce 1 mole of iron oxide and 4 moles of hydrogen gas.

The mole ratio of $Fe_3O_4:Fe=1:3$

Hence, the correct answer is Option A.

7 0

3 years ago

Read 2 more answers

H2(g) + Co(g) _CH3OH balance the equation

Tom [10]

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

C: 1a + 0b = 1c

O: 1a + 0b = 1c

H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 1

b = 2

c = 1

4. Substitute Coefficients and Verify Result

CO + 2H2 = CH3OH

L R

C: 1 1 ✔️

O: 1 1 ✔️

H: 4 4 ✔️

8 0

2 years ago

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

Answer: The concentration of $NH_3$ required will be 0.285 M.

Explanation:

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

3 years ago