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Aleonysh [2.5K]
3 years ago
10

Which compound is an exception to the octet rule?

Chemistry
2 answers:
slavikrds [6]3 years ago
8 0

Answer:

the answer is ClF3 on edge

Explanation:

viva [34]3 years ago
5 0

Answer:

CIF3

Explanation:

I just took the test

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Estimate the air pressure at an altitude of 5km
r-ruslan [8.4K]
The answer is 100 kg
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3 years ago
Which statement best describes the whether shown by the purple combination of semicircles and triangles on a line on a weather m
iren2701 [21]
It seems that you have missed to attach the given map and options for us to answer this question, so I had to look for it. Anyway, here is the answer. The statement that best describes the whether shown by the purple combination of semicircles and triangles on a line on a weather map is a <span>cold front can cause heavy rain, thunder, and lightning. Hope this helps.</span>
3 0
4 years ago
Read 2 more answers
A penny has a mass of 2.50g and the Moon has a mass of ×7.351022kg, How many moles of pennies have a mass equal to the mass of t
baherus [9]
Answer: 122 moles

Procedure:

1) Convert all the units to the same unit

2) mass of a penny = 2.50 g

3) mass of the Moon = 7.35 * 10^22 kg (I had to arrage your numbers because it was wrong).

=> 7.35 * 10^22 kg * 1000 g / kg = 7.35 * 10^ 25 g.

4) find how many times the mass of a penny is contained in the mass of the Moon.

You have to divide the mass of the Moon by the mass of a penny

7.35 * 10^ 25 g / 2.50 g = 2.94 * 10^25 pennies

That means that 2.94 * 10^ 25 pennies have the mass of the Moon, which you can check by mulitiplying the mass of one penny times the number ob pennies: 2.50 g * 2.94 * 10^25 = 7.35 * 10^25.

5) Convert the number of pennies into mole unit. That is using Avogadros's number: 6.022 * 10^ 23

7.35 * 10^ 25 penny * 1 mol / (6.022 * 10^ 23 penny) = 1.22* 10^ 2 mole = 122 mol.

Answer: 122 mol
8 0
3 years ago
i have a crossword thing that i got from school and one of the clues is: If there are two equal and opposite forces on something
cluponka [151]
I would assume the answer is called attractive
6 0
3 years ago
Read 2 more answers
1.15.7 cm3 of HCl completely neutralised 25 cm3 of LiOH. The HCl was 2 mol/dm3.The equation is :
Whitepunk [10]

Answer:

C₂ = 1.26 mol/dm³

Explanation:

Given data:

Volume of HCl =V₁ =  15.7 cm³

Volume of LiOH = V₂ =  25 cm³

Concentration of HCl =C₁ = 2 mol/dm³

Concentration of LiOH =C₂=  ?

Solution:

Chemical equation:

LiOH + HCl    →     LiCl + H₂O

Formula:

C₁V₁   = C₂V₂

by putting values,

15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³

C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³

C₂ = 31.4 cm₃.mol/dm³ / 25 cm³

C₂ = 1.26 mol/dm³

8 0
3 years ago
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