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nordsb [41]
3 years ago
8

What is the molarity of 0.65 mol NaF dissolved in a total volume of 0.50 liters?

Chemistry
1 answer:
arsen [322]3 years ago
5 0

Answer:

1.3 M

Explanation:

The question asks to calculate the molarity of a solution.

We have to use the following equitation:

Molarity = # moles / 1 lt of solution

In this case we have a solution composed of 0.65 mol of NaF diluted in a total volume of 0.5 lt. We will have to do the following cross multiplication solving for x:

0.65 mol NaF / 0.5 lt = x mol NaF/ 1 lt

x = 1.3 mol NaF / 1 lt = 1.3 M

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Kitty [74]

Answer:

1.5 hours or 90 minutes

Explanation:

Velocity = d/t

V = 64 mi / hour or 96 mi / 9 min OR 16 mi / 15 min

D = 96 miles

Velocity * Time = Distance

Time = Distance / Velocity

T = 96 mi / 64 mi / hour

96 / 64 = 1.5 mi per hour

T = 1.5 hours or 90 minutes

4 0
3 years ago
What is the ph of a solution made by mixing 25.00 ml of 0.100 m hcl with 40.00 ml of 0.100 m koh? assume that the volumes of the
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<span>Answer: The HCl and KOH will react until one or the other is gone. As you have a larger volume of an equal concentration of HCl, the KOH will go first. moles HCl = 0.04000 L * 0.100 M = 0.00400 moles moles KOH = 0.02500 L * 0.100 M = 0.00250 moles moles HCl left = 0.00400 - 0.00250 = 0.00150 moles Your total volume is now 65.00 mL, so the [HCl] = 0.00150 moles / 0.06500 L = 0.0231 M = [H+] pH = -log [H+] = -log (0.0231) = 1.64</span>
3 0
3 years ago
A 508-g sample of sodium bicarbonate (NaHCO3) contains how many moles of sodium bicarbonate (NaHCO3)?
Blizzard [7]

molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)

molar mass = 84.01 g/mol

//

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3 0
3 years ago
Which of the following electron configurations gives the correct arrangement of the four valence electrons of the carbon atom in
Juliette [100K]

Answer:

D) 2s^12p^3

Explanation:

Carbon.

The electronic configuration is -  

1s^22s^22p^2

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

But in methane, CH_4 it forms 4 bonds. So, 1 electron each from 2s orbital jumps to the next orbital in the p subshell.

Thus, the configuration is:-

1s^22s^22p^2

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2s^12p^3

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3 years ago
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4 0
2 years ago
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