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3 years ago

What is the molarity of 0.65 mol NaF dissolved in a total volume of 0.50 liters?

Chemistry

1 answer:

arsen [322]3 years ago

5 0

Answer:

1.3 M

Explanation:

The question asks to calculate the molarity of a solution.

We have to use the following equitation:

Molarity = # moles / 1 lt of solution

In this case we have a solution composed of 0.65 mol of NaF diluted in a total volume of 0.5 lt. We will have to do the following cross multiplication solving for x:

0.65 mol NaF / 0.5 lt = x mol NaF/ 1 lt

x = 1.3 mol NaF / 1 lt = 1.3 M

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9. If 28.56 g of K2O is produced when 25.00 g K is reactedaccording to the following equation, what is the percent yieldof the r

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Answer

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Explanation

Given:

Mass of K₂O produced (actual yield) = 28.56 g

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What to find:

The percent yield of K₂O.

Step-by-step solution:

The first step is to calculate the theoretical yield of K₂O produced.

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Theoretical yield of k₂O = 30.1151 g

The percent yield for the reaction can now be calculated using the formula below:

$\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\ \\ Percent\text{ }yield=\frac{28.56\text{ }g}{30.1151\text{ }g}\times100\% \\ \\ Percent\text{ }yield=0.9484\times100\% \\ \\ Percent\text{ }yield=94.84\%\approx95\% \end{gathered}$

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