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vazorg [7]
2 years ago
11

Problem Page What kind of intermolecular forces act between a formaldehyde molecule and a hydrogen sulfide molecule? Note: If th

ere is more than one type of intermolecular force that acts, be sure to list them all, with a comma between the name of each force. Clears your work. Undoes your last action. Provides information about entering answers.
Chemistry
1 answer:
malfutka [58]2 years ago
8 0

Answer:

Hydrogen Bonding

Explanation:

Formaldehyde, H2CO, has an oxygen atom which is quite electronegative that means it would attract any atom with a slightly positive charge. Hydrogen in the Hydrogen sulfide (H2S) is attracted by oxygen and hence hydrogen bonding can occur.

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A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a
san4es73 [151]

Answer:

A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a simple substitution reaction or simple displacement reaction.

Explanation:

A simple substitution reaction or simple displacement reaction, called single-displacement reaction, is a reaction in which an element of a compound is substituted by another element involved in the reaction. The starting materials are always pure elements and an aqueous compound. And a new pure aqueous compound and a different pure element are generated as products. The general form of a simple substitution reaction is:

AB + C → A +BC

where C and A are pure elements; C replaces A within compound AB to form a new co, placed CB and elementary A.

So, in a Single replacement reaction an uncombined element replaces an element.

<u><em>A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a simple substitution reaction or simple displacement reaction.</em></u>

3 0
2 years ago
While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting e
sp2606 [1]

The question is incomplete, here is the complete question:

While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene with water vapor at elevated temperatures.

A chemical engineer studying this reaction fills a 1.5 L flask at 12°C with 1.8 atm of ethylene gas and 4.7 atm of water vapor. When the mixture has come to equilibrium she determines that it contains 1.16 atm of ethylene gas and 4.06 atm of water vapor.

The engineer then adds another 1.2 atm of ethylene, and allows the mixture to come to equilibrium again. Calculate the pressure of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits.

<u>Answer:</u> The partial pressure of ethanol after equilibrium is reached the second time is 1.0 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of ethylene gas = 1.8 atm

Initial partial pressure of water vapor = 4.7 atm

Equilibrium partial pressure of ethylene gas = 1.16 atm

Equilibrium partial pressure of water vapor = 4.06 atm

The chemical equation for the reaction of ethylene gas and water vapor follows:

                     CH_2CH_2(g)+H_2O(g)\rightleftharpoons CH_3CH_2OH(g)

<u>Initial:</u>                  1.8                4.7

<u>At eqllm:</u>           1.8-x             4.7-x

Evaluating the value of 'x'

\Rightarrow (1.8-x)=1.16\\\\x=0.64

The expression of K_p for above equation follows:

K_p=\frac{p_{CH_3CH_2OH}}{p_{CH_2CH_2}\times p_{H_2O}}

p_{CH_2CH_2}=1.16atm\\p_{H_2O}=4.06atm\\p_{CH_3CH_2OH}=0.64atm

Putting values in above expression, we get:

K_p=\frac{0.64}{1.16\times 4.06}\\\\K_p=0.136

When more ethylene is added, the equilibrium gets re-established.

Partial pressure of ethylene added = 1.2 atm

                     CH_2CH_2(g)+H_2O(g)\rightleftharpoons CH_3CH_2OH(g)

<u>Initial:</u>                2.36             4.06               0.64

<u>At eqllm:</u>           2.36-x        4.06-x             0.64+x

Putting value in the equilibrium constant expression, we get:

0.136=\frac{(0.64+x)}{(2.36-x)\times (4.06-x)}\\\\x=0.363,13.41

Neglecting the value of x = 13.41 because equilibrium partial pressure of ethylene and water vapor will become negative, which is not possible.

So, equilibrium partial pressure of ethanol = (0.64 + x) = (0.64 + 0.363) = 1.003 atm

Hence, the partial pressure of ethanol after equilibrium is reached the second time is 1.0 atm

3 0
3 years ago
Predict the products for the following chemical reaction: H2 + O2 →
RSB [31]
The answer is C I got it right so hope it helped ;)
6 0
3 years ago
How is agriculture depended on industries​
gulaghasi [49]

Answer:

The interdependence of agriculture and industry helps the development of both the sectors. The most important aspect of this inter dependence is that the products of one serve as important inputs for the other. Growth of one sector, thus means ample supply of inputs for the other.

Explanation:

3 0
2 years ago
5. What is the partial pressure of the remaining gas, if the total is 384 torr 2
alexgriva [62]

Answer: 83.11 torr

Explanation:

According to Dalton's Law of partial pressure, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.

i.e Ptotal = P1 + P2 + P3 + .......

In this case,

Ptotal = 384 torr

P1 = 289 torr

P2 = 11.89 torr

P3 = ? (let the partial pressure of the remaining gas be Z)

Ptotal = P1 + P2 + Z

384 torr = 289 torr + 11.89 torr + Z

384 torr = 300.89 torr + Z

Z = 384 torr - 300.89 torr

Z = 83.11 torr

Thus, the partial pressure of the remaining gas is 83.11 torr.

5 0
3 years ago
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