Answer:
Silver Acetate would be the Limiting Reagent.
Explanation:
The balance chemical equation for the given double displacement reaction is as;
HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂
Step 1: <u>Calculate Moles of Starting Materials:</u>
Moles of HCl:
Moles = Mass / M.Mass
Moles = 72.9 g / 36.46
Moles = 1.99 moles
Moles of AgC₂H₃O₂:
Moles = 150 g / 166.91 g/mol
Moles = 0.898 moles
Step 2: <u>Find out Limiting reagent as:</u>
According to balance chemical equation.
1 mole of HCl reacts with = 1 mole of AgC₂H₃O₂
So,
1.99 moles of HCl will react with = X moles of AgC₂H₃O₂
Solving for X,
X = 1.99 mol × 1 mol / 1 mol
X = 1.99 mol of AgC₂H₃O₂
Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.
The
answer is:
glucose,
a polar organic compound
silver
nitrate, an ionic compound
<span>The two have net charges
that enable them to attract with water molecules. Water molecules are partly
charged because of the arrangement of electron clouds around the molecule. The oxygen
atom in the molecule is more electronegative
than the two hydrogens. Therefore water is able to
form electrostatic attraction forces with
the charged molecules</span>
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➷ The formula for Potassium oxide is K2O
This is because potassium has a 1+ charge and the oxygen has a 2- charge. Two potassium atoms are required to balance the charge.
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The interphase usually lasts the longest
The answer is b)h2o is a compund