This question is incomplete, the complete question is;
Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?
Answer: the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343
Explanation:
We know that when Unpolarized light passes through first polarizer, it's intensity will be reduced to half i.e
I1 = I0/2
Now after that when light passes through 2nd polarizer, Intensity will be;
I2 = I1 × (cos A1)²
but I1 = I0/2
so
I2 = (I0/2) × (cos A1)²
I2/I0 = 0.5 × (cos A1)²
In the question we were given that; The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer
so A = 34°
so we substitute
I2/I0 = 0.5 × (cos 34)²
I2/I0 = 0.343
Therefore the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343
Answer;
offgassing
Explanation;
The removal of the embedded gas from a solid object, as happens when formaldehyde in new carpets & furniture is released into the air, is a process known as
offgassing.
It occurs when new, manufactured items in our homes release volatile organic compounds (VOCs) and other chemicals. These compounds include, paints, glue, finishes, among others, they release gases into air.
<span>The weight lifted by a machine to the applied force on a machine is called mechanical advantage.
This is written as Mechanical advantage, M. A, = load(weight)/effort.
So for 1) M.A = 2 and load = 2, 000lb = 8896.446N.
So 2 = 8896.446/ effort
Effort = 8896.446/2 = 4448.48
Similarly for M.A of 2, 000, 000 we have
Effort = 8896.446/ 2, 000, 000 = 0.004448</span>
Explanation:
KE = 1/2mv^2
6,250 J =1/2(250kg) v ^2
<u>6250 J </u>= <u>125kgv^2</u>
125kg. 125kg
v =

Answer:
G M m / R^2 = m v^2 / R gravitational force = centripetal force
G M = v^2 R = constant
As v increases R will must decrease
Take the moon as an example
S = 2 pi R where R is about 240,000 miles for one orbit
S / 1 day = 54,000 miles/day for a 28 day circuit
S / 1 hr = 54000 / 24 = 2200 mph which is much less than a satellite in orbit