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mr_godi [17]
3 years ago
14

What’s the equalibrium rule?

Physics
2 answers:
Hoochie [10]3 years ago
7 0
The 50 N force is not equal to the 30 N force. If an object is at equilibrium, then the forces are balanced. Balanced is the key word that is used to describeequilibrium situations. Thus, the net force is zero and the acceleration is 0 m/s/s.
ale4655 [162]3 years ago
4 0
The vector sum of forces acting on a non-accelerating object equals zero.
equation form: ΣF = 0
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What is the rate of 12 liters of water moving through a water hose in 4.0 minutes?
Basile [38]
3 liters per minute
6 0
3 years ago
You travel an an average speed of 20 km/h in a straight line to get to your grandmothers house. It takes you 3 hours to get to h
Ber [7]
20km every 1 hr is what 20km/hr means.

so 3hrs is 20km*3=60km.
6 0
3 years ago
In a collision, a 25.0 kg mass moving at 3.0 m/s transfers all of its momentum to a 5.0 kg mass.
nadezda [96]

Answer:

Explanation:

The momentum of the 25 kg mass is

p=mv

p=25kg*3m/s= 75kg*m/s

If this whole momentum of the object is transferred to the 5.0 kg object then according to the law of conservation of momentum, the momentum of the 25.0 kg object must be transferred to the 5.0 kg object:

75kg*m/s = 5.0kg*v

v=\dfrac{75}{5}

\boxed{v=15m/s}

8 0
3 years ago
A bicycle tire has a pressure of 7.00×105 N/m2 at a temperature of 18.0ºC and contains 2.00 L of gas. What will its pressure be
stepan [7]

Answer:

p_2 = 664081 N/m^{2}

Explanation:

from the ideal gas law we have

PV = mRT

P = \rho RT

\rho = \frac{P}{RT}

HERE  R is gas constant for dry air  =  287  J K^{-1} kg^{-1}

\rho = \frac{7.00 10^{5}}{287(18+273)}

\rho = 8.38 kg/m^{3}

We know by ideal gas law

\rho = \frac{m_1}{V_1}

m_1 = \rho V_1 = 8.38 *2*10^{-3}

m_1 = 0.0167 kg

for m_2

m_2 = \rho V_i - V_removed

m_2 = 8.38*(.002 - 10^{-4})

m_2 = 0.0159 kg

WE KNOW

PV = mRT

V, R and T are constant therefore we have

P is directly proportional to mass

\frac{p_2}{p_1}=\frac{m_2}{m_1}

p_2 = p_1 * \frac{m_2}{m_1}

p_2 =7*10^{5} * \frac {.0159}{0.0167}

p_2 = 664081 N/m^{2}

8 0
2 years ago
which religious group did not expand their membership by great numbers during the Second Great Awakening
Dimas [21]

Answer:

The Catholics.

Explanation:

see answer.

4 0
2 years ago
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