Answer:
Acceleration of the car is
.
Explanation:
It is given that,
Initial speed of the car, u = 29 m/s
Finally it reaches a speed of, v = 34 m/s
Distance, d = 110 m
We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :




So, the acceleration of the car as it speeds up is
. Hence, this is the required solution.
Answer:
a

b
Explanation:
From the question we are told that
The total mass of three people is 
The mass of the car is 
The compression of the car spring is 
Generally the spring constant is mathematically represented as

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as
=> 
=> ![F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8](https://tex.z-dn.net/?f=F%20%3D%20%28%5B2.0%2A10%5E%7B2%7D%20%5D%2B%5B%201.200%2A10%5E%7B3%7D%5D%29%20%2A%209.8)
=> 
So

=> 
Generally if the mass which the car is loaded with is 
Then the force experienced by the spring is
=> 
=> 
=> 
Generally from the above formula the compression is

=> 
=>
Answer:
a) V = k 2π σ (√(b² + x²) - √ (a² + x²))
,
b) E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))
Explanation:
a) The expression for the electric potential is
V = k ∫ dq / r
For this case, consider the disk formed by a series of concentric rings of radius r and width dr, the distance of each ring to point P
R = √(x² + r²)
The charge on a ring is
σ = dq / dA
The area of a ring is
A = π r
dA = 2π r dr
So the charge is
dq = σ 2π r dr
We substitute
V = k σ 2pi ∫ r dr / √(r² + x²)
We integrate
V = k 2π σ √(r² + x²)
We evaluate from the lower limit r = a to the upper limit r = b
V = k 2π σ (√(b² + x²) - √ (a² + x²))
b) the electric field and the potential are related
E = - dV / dx
E = - k 2π σ (1/2 2x /√(b² + x²) - ½ 2x /√(a² + x²))
E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))
"D. Both have electrons that orbit the atomic nucleus in a similar way ." is not shared by Bohr's model and the modern atomic model.
Hope this helps,
Davinia.