This question sounds like it came after some activity where
some forces were observed. Since we were not there, and
we don't know what the activity was, we don't know what forces
were observed, and we have no clue to how they might be related
to the motion of the Earth around the sun.
It is 29 and a half days long
Answer:
v = 66 m/s
Explanation:
Given that,
The initial velocity of a car, u = 0
Acceleration of the car, a = 11 m/s²
We need to find the final velocity of the toy after 6 seconds.
Let v is the final velocity. It can be calculated using first equation of motion. It is given by :
v = u +at
v = 0 + 11 m/s² × 6 s
v = 66 m/s
So, the final velocity of the car is 66 m/s.
Answer:
0.015 atm
Explanation:
The pressure of the gas can be calculated using Ideal Gas Law:

<u>Where:</u>
n: is the number of moles of the gas
R: is the gas constant = 0.082 L*atm/(K*mol)
V: is the volume of the container = 1.64 L
T: is the temperature
We need to find the number of moles and the temperature. The number of moles is:

<u>Where:</u>
M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol
m: is the mass of the gas = 0.226 g

Now, the temperature can be found using the following equation:
<u>Where:</u>
R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol
: is the root-mean-square speed of the gas = 182 m/s
By solving the above equation for T, we have:
Finally, we can find the pressure of the gas:

Therefore, the pressure of the gas is 0.015 atm.
I hope it helps you!
Answer:
108.7 V
Explanation:
Two forces are acting on the particle:
- The external force, whose work is 
- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: 
where
q is the charge
is the potential difference
The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

and since the charge starts from rest,
, so the formula becomes

In this problem, we have
is the work done by the external force
is the charge
is the final kinetic energy
Solving the formula for
, we find
