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jenyasd209 [6]
3 years ago
9

There were 276 people on air airplane write a number greater than 276

Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0
277 good luck on whatever you need this for
jeka943 years ago
5 0
A few examples of a number greater than 276 are 277, 373, 4,737

Hope this helps you!
-PsychoChicken4040
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Does this graph represent a function? Why or why not?
RoseWind [281]

Answer:

D

Step-by-step explanation:

There are no two points on the same line so the answer is D

I hope this is right!

6 0
3 years ago
Y -3 =9 solve for y 4w = 24 solve for w y -3 =9 solve for y
gayaneshka [121]
Y=12
Add 3 to both sides add nine and 3 to get 12

W=6
Divide both sides by four divide 24 by 4 to get six

X=2
Subtract eight from both sides
subtract eight from 10 to get 2
7 0
2 years ago
Read 2 more answers
3x-5=2(2x+5) how do you slove it
DaniilM [7]

Answer:

x = -15

Step-by-step explanation:

3x-5=2(2x+5)

Expand by using distributive property

3x - 5 = 4x + 10

Subtract 4x from both sides

3x - 5 - 4x = 4x + 10 - 4x

Simplifying

-x - 5 = 10

Add 5 to both sides

-x - 5 + 5 = 10 + 5

Simplifying

-x = 15

Divide both sides by -1

x = -15

5 0
2 years ago
Please help
MArishka [77]
2^4x-2^3x-3

2^3=2x2x2
Which equals 8
3 0
3 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
2 years ago
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