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3 years ago

What is the density of a mineral with a mass of 41.2 g and a volume 8.2 cm3?

Chemistry

2 answers:

Tanya [424]3 years ago

7 0

Answer : The density of a mineral is, 5.024 g/ml

Solution : Given,

Mass of mineral = 41.2 g

Volume of mineral = $8.2cm^3=8.2ml$ $(1cm^3=1ml)$

Formula used :

$Density=\frac{Mass}{Volume}$

Now put all the given values in this formula, we get the density of mineral.

$Density=\frac{41.2g}{8.2ml}=5.02g/ml$

Therefore, the density of a mineral is, 5.024 g/ml

dezoksy [38]3 years ago

4 0

Hey there!:

mass = 41.2 g

Volume = 8.2 cm³

Therefore:

D = m / V

D = 41.2 / 8.2

D = 5.02 g/cm³

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3 years ago

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Ne4ueva [31]

Answer:

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2 years ago

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