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3 years ago

15

In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at

which the wrecking ball strikes the building.

2 answers:

Arlecino [84]3 years ago

8 0

F=ma
f?
m=1300kg
a=1.07m\s squared
f=1300kg x 1.07=1391N

Verdich [7]3 years ago

3 0

The answer is: 1391N

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Answer:

Explanation:

Center of mass is give as

Xcm = (Σmi•xi) / M

Where i= 1,2,3,4.....

M = m1+m2+m3 +....

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Now,

Given that,

u1 = (−1, 0, 2) (mass 3 kg),

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u2 = (2, 1, −3) (mass 1 kg),

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u3 = (0, 4, 3) (mass 2 kg),

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u4 = (5, 2, 0) (mass 5 kg)

m4 = 5kg and it position x4 = (5,2,0)

Now, applying center of mass formula

Xcm = (Σmi•xi) / M

Xcm = (m1•x1+m2•x2+m3•x3+m4•x4) / (m1+m2+m3+m4)

Xcm = [3(-1, 0, 2) +1(2, 1, -3)+2(0, 4, 3)+ 5(5, 2, 0)]/(3 + 1 + 2 + 5)

Xcm = [(-3, 0, 6)+(2, 1, -3)+(0, 8, 6)+(25, 10, 0)] / 11

Xcm = (-3+2+0+25, 0+1+8+10, 6-3+6+0) / 11

Xcm = (24, 19, 9) / 11

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This is the required center of mass

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3 years ago

Why are there only two elements in the first period of the periodic table?(1 point)

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Answer:

because only two electrons can fit in the first orbit around the nucleus, and each period on the table is organized by number of orbits

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2 years ago

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Answer:

m = 35.98 Kg ≈ 36 Kg

Explanation:

I₀ = 125 kg·m²

R₁ = 1.50 m

ωi = 0.600 rad/s

R₂ = 0.905 m

ωf = 0.800 rad/s

m = ?

We can apply The law of conservation of angular momentum as follows:

Linitial = Lfinal

⇒ Ii*ωi = If*ωf <em>(I)</em>

where

Ii = I₀ + m*R₁² = 125 + m*(1.50)² = 125 + 2.25*m

If = I₀ + m*R₂² = 125 + m*(0.905)² = 125 + 0.819025*m

Now, we using the equation <em>(I) </em>we have

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3 years ago

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Answer:

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3 years ago

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Answer:

Explanation:

A )

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3 years ago