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kolbaska11 [484]
3 years ago
11

What aspects of bone’s structure make it stronger than concrete? think about the engineering design of bone. use the terms tensi

le strength and compressional strength in your answer?
Physics
1 answer:
marissa [1.9K]3 years ago
4 0
<span>The bone is made up of calcium. Calcium along with collagen helps to make the bones very strong, like concrete. Bones have a very high tensile strength, that is why we can put the pressure of our body weight on them without the bones being broken immediately. The structure of the bone also helps since the shaft is made up of compact bone which is very good at resisting tension. To help with the compressional strength of the bones, the extremities are made of cancellous material which is very good at fighting compression. All in all, the material and engineering of the bone allow it to be rigid, yet flexible, making them hard to break and good at their function of support and protection.</span>
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Copper has a specific heat of 387 J/kg°C. A copper bullet is moving at 950 m/s. If the bullet is suddenly stopped so that all of
Alla [95]

Answer:

1196.02 °C

Explanation:

If the kinetic energy is converted into heat,

then,

Kinetic energy of the copper = heat energy of the copper

1/2m(v²) = cm(t₂-t₁)

where m = mass of copper, v =  velocity of copper, c = specific heat capacity of copper, t₂ = final temperature of copper, t₁ = initial temperature of copper.

Since the mass of copper remains the same,

1/2v² = c(t₂-t₁)

make t₂ the subject of the equation

t₂ = 1/2(v²/c)+t₁..................... Equation 1

Given: v = 950 m/s, c = 387 J/kg°C, t₁ 30 °C

Substitute into equation 1

t₂ = 1/2(950²/387)+30

t₂ = 1196.02 °C

Hence the temperature the bullet reach before it was stopped = 1196.02 °C

8 0
3 years ago
A 70.0 kg base runner moving at a speed of 4.0 m/s begins his slide into second base. The coefficient of friction between his cl
Andre45 [30]

Answer:

B. 560 J

J. 1.2 m

Explanation:

v = Final velocity = 0

u = Initial velocity = 4 m/s

\mu = Coefficient of friction = 0.7

m = Mass of runner = 70 kg

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Kinetic energy is given by

K=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow K=\dfrac{1}{2}\times 70\times (0^2-4^2)\\\Rightarrow K=-560\ \text{J}

The mechanical energy lost is 560 J

Acceleration is given by

a=-\mu g\\\Rightarrow a=-0.7\times 9.81\\\Rightarrow a=-6.867\ \text{m/s}^2

From kinematic equations we get

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-4^2}{2\times -6.867}\\\Rightarrow s=1.165\approx 1.2\ \text{m}

The runner slides for 1.2 m

4 0
3 years ago
What is the relationship between mass and inertia? Give an example
ad-work [718]

Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it ha

5 0
3 years ago
A certain radioactive isotope has a half-life of approximately 900 years. How many years to the nearest year would be required f
White raven [17]

Answer:

cevap ekterir iyi dersler

7 0
3 years ago
A proton moving at 3.90 106 m/s through a magnetic field of magnitude 1.80 T experiences a magnetic force of magnitude 7.20 10-1
VARVARA [1.3K]

Answer:

\theta=40^0

Explanation:

The magnitude of the magnetic force is

F_m=evB\sin\theta

To find the angle, we make \sin\theta subject of the formula

\implies \sin\theta=\frac{F_m}{evB}=\frac{7.20\times 10^{-13}}{1.6\times 10^{-19}\times 3.90\times 10^6\times 1.80}

\implies \sin\theta=0.641025641

\therefore \theta=\sin^{-1}=39.8683^0\\\implies \theta\approxeq 40^0

8 0
3 years ago
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