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3 years ago

In order to move a bag of dog food across a 10 meter room you apply20 Newton’s of force how much work was done?

Physics

1 answer:

lilavasa [31]3 years ago

8 0

The work done is calculated by multiplying the Force by the distance. So, 10x20 = 200 joules.
I hope this is the answer you are looking for, if not good luck on finding your answer ;D

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V=xf-xi/t solve for t

irina [24]

Answer:

$t=\frac{x_f-x_i}{v}$

Explanation:

Starting from the equation:

$v=\frac{x_f-x_i}{t}$

First of all, let's multiply by t on both sides:

$v\cdot t = \frac{x_f-x_i}{t}\cdot t \\vt = x_f - x_i$

And then, let's divide by v on both sides:

$\frac{vt}{v}=\frac{x_f-x_i}{v}\\t=\frac{x_f-x_i}{v}$

So, finally

$t=\frac{x_f-x_i}{v}$

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3 years ago

In one cycle a heat engine absorbs 450 J from a high-temperature reservoir and expels 290 J to a low-temperature reservoir. If t

Vitek1552 [10]

Answer:

So the ratio will be $\frac{T_L}{T_H}=-0.171$

Explanation:

We have given heat engine absorbs 450 joule from high temperature reservoir

So $Q=450j$

As the heat engine expels 290 j

So work done W = 290 J

We know that efficiency $\eta =\frac{W}{Q}=\frac{290}{450}=0.6444$

It is given that efficiency of the engine only 55 % of Carnot engine

So efficiency of Carnot engine $=\frac{0.6444}{0.55}=1.171$

Efficiency of Carnot engine is $\eta =1-\frac{T_L}{T_H}$

$1.171 =1-\frac{T_L}{T_H}$

$\frac{T_L}{T_H}=-0.171$

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A bag weighing 20 N is pushed horizontally a distance of 35 m across a

topjm [15]

Answer:

350J

Explanation:

Given parameters:

Weight of bag = 20N

Distance moved horizontally = 35m

Force applied = 10N

Unknown:

Work done on the bag = ?

Solution:

Work done is the force applied to move a body through given distance.

Work done = Force applied x distance

So;

Work done = 10 x 35 = 350J

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The answer is C.rationing.

<span>♡♡Hope I helped!!! :)♡♡
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Explanation:

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